python标签的Scrapy提取值

Question

I'm new to Scrapy and I'm trying to scrape a page that has an aria-label on a class: 我是Scrapy的新手，我正在尝试抓取在类上具有aria标签的页面：

<body>
  <div class="item-price" aria-label="$1.99">
    .....
  </div>
</body>

I'm trying to extract the label with the following parse on my spider: 我正在尝试对蜘蛛进行以下解析来提取标签：

def parse(self, response):
   price = circular_item.css("div.item-price > aria-label::text").extract()
   yield price

When I run the spider I get the following error: 当我运行蜘蛛时，出现以下错误：

2018-09-02 18:34:03 [scrapy.core.scraper] ERROR: Spider must return Request, BaseItem, dict or None, got 'list' in <GET https://example.com/test.html>

How do I extract the value of aria-label here? 如何在此处提取aria标签的价值？

Answer 1

You have several errors in your code: 您的代码中有几个错误：

def parse(self, response):
   item = {}
   item["price"] = response.xpath('//div[@class="item-price"]/@aria-label').extract_first()
   yield item

Answer 2

If you want to use a css extractor instead of xpath: 如果要使用css提取器而不是xpath：

def parse(self, response):
    item = {response.css('div.item-price::attr(aria-label)').extract_first()}
    yield item

python标签的Scrapy提取值

问题描述

2 个解决方案

解决方案1
1 已采纳 2018-09-02 23:18:40

解决方案2
1 2018-09-03 09:36:14

python标签的Scrapy提取值

问题描述

2 个解决方案

解决方案1 1 已采纳 2018-09-02 23:18:40

解决方案2 1 2018-09-03 09:36:14

解决方案1
1 已采纳 2018-09-02 23:18:40

解决方案2
1 2018-09-03 09:36:14