如何合并包含相同对象键的多个子数组？

Question

Can someone help me with this, please? I've spent a long time trying to figure it out. I have the following format:

[
  [{id:'1',venue:'foa',title:'t'},{id:'5',venue:'cs',title:'b'}, ...],
  [{id:'2',venue:'fob',title:'t'},{id:'6',venue:'cs',title:'b'}, ...],    
  [{id:'3',venue:'foc',title:'t'},{id:'7',venue:'cs',title:'b'}, ...],
  [{id:'4',venue:'fod',title:'t'},{id:'8',venue:'cs',title:'b'}, ...]
]

what is the simplest way to make it in this format (._underscore preferably):

{id:'1',venue:'foa',title:'t'}
{id:'5',venue:'cs',title:'b'}
{id:'2',venue:'fob',title:'t'}
{id:'6',venue:'cs',title:'b'}
{id:'3',venue:'foc',title:'t'}
{id:'7',venue:'cs',title:'b'}
{id:'4',venue:'fod',title:'t'}
{id:'8',venue:'cs',title:'b'}

Answer 1

Your question is not clear enough but if you just want to flatten your array, you can use the below code:

 var arr = [ [{id:'1',venue:'foa',title:'t'},{id:'5',venue:'cs',title:'b'}], [{id:'2',venue:'fob',title:'t'},{id:'6',venue:'cs',title:'b'}], [{id:'3',venue:'foc',title:'t'},{id:'7',venue:'cs',title:'b'}], [{id:'4',venue:'fod',title:'t'},{id:'8',venue:'cs',title:'b'}] ]; var res = [].concat(...arr); console.log(res); 

Answer 2

I'm not sure what exactly you want but here's what you can try using Lodash:

 var result = []; var obj = [ [{id:'1',venue:'foa',title:'t'},{id:'5',venue:'cs',title:'b'}], [{id:'2',venue:'fob',title:'t'},{id:'6',venue:'cs',title:'b'}], [{id:'3',venue:'foc',title:'t'},{id:'7',venue:'cs',title:'b'}], [{id:'4',venue:'fod',title:'t'},{id:'8',venue:'cs',title:'b'}] ]; _.each(obj, function(i) { _.each(i, function(j) { result.push(j); }); }); console.log(result); 

 <script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.10/lodash.js"></script> 

Answer 3

You can use flatten() .

 var arr = [[{id:'1',venue:'foa',title:'t'},{id:'5',venue:'cs',title:'b'}],[{id:'2',venue:'fob',title:'t'},{id:'6',venue:'cs',title:'b'}], [{id:'3',venue:'foc',title:'t'},{id:'7',venue:'cs',title:'b'}],[{id:'4',venue:'fod',title:'t'},{id:'8',venue:'cs',title:'b'}]], result = _.flatten(arr); console.log(result); 

 <script src="https://cdnjs.cloudflare.com/ajax/libs/underscore.js/1.9.1/underscore-min.js"></script>