[英]Jinja2 check if value exists in list of dictionaries
I am trying to check if a value exists inside a list with dictionaries. 我正在尝试检查包含字典的列表中是否存在值。 I use flask 1.0.2.
我使用烧瓶1.0.2。 See example below:
请参见下面的示例:
person_list_dict = [
{
"name": "John Doe",
"email": "johndoe@mydomain.com",
"rol": "admin"
},
{
"name": "John Smith",
"email": "johnsmith@mydomain.com",
"rol": "user"
}
]
I found two ways to solve this problem, can you tell me which is better?: 我找到了两种方法可以解决此问题,您能告诉我哪个更好吗?:
<pre>{% if "admin" in person_list_dict|map(attribute="rol") %}YES{% else %}NOPE{% endif %}</pre>
# return YES (john doe) and NOPE (john smith)
Flask code: 烧瓶代码:
@app.template_filter("is_in_list_dict")
def is_any(search="", list_dict=None, dict_key=""):
if any(search in element[dict_key] for element in list_dict):
return True
return False
Template code: 模板代码:
<pre>{% if "admin"|is_in_list_dict(person_list_dict, "rol") %} YES {% else %} NOPE {% endif %}</pre>
# return YES (john doe) and NOPE (john smith)
Thanks :-). 谢谢 :-)。
If possible, I would move this logic to the python part of the script before rendering it in Jinja. 如果可能的话,在将其添加到Jinja中之前,我会将此逻辑移至脚本的python部分。 Because, as stated in the Jinja documentation : "Without a doubt you should try to remove as much logic from templates as possible."
因为,正如Jinja文档中所述:“毫无疑问,您应该尝试从模板中删除尽可能多的逻辑。”
any([person['role'] == 'admin' for person in person_dict_list])
is a lot easier to follow at first glance than the other 2 options. 与其他两个选项相比,
any([person['role'] == 'admin' for person in person_dict_list])
乍一看要容易得多。
If that's not an option, I would probably use the first, build in function, because I think it's less prone to errors in edge cases as your own solution, and is about 6x less code. 如果这不是一个选择,那么我可能会使用第一个内置函数,因为我认为它作为自己的解决方案在边缘情况下不太容易出错,并且代码减少了约6倍。
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