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如何使用 java 中的 useDelimeter 从字符串中获取两个特定值?

[英]How can i get two specific values from a String using useDelimeter in java?

I am trying to get the two player values from "line" String and insert them into player1 and player2, using regular expression.我正在尝试使用正则表达式从“line”字符串中获取两个玩家值并将它们插入到 player1 和 player2 中。

   try (BufferedReader in = new BufferedReader(new FileReader(file))) {

        String line;
        String player1;
        String player2;

        while ((line = in.readLine()) != null) {
            Scanner input = new Scanner(line);

            input.useDelimiter("(.* [a-z] )|\\sby ");

            if(line.toLowerCase().contains("kill")) {
                kill +=  1;

                //i would like to set the player1 and player2 here
            }                   
        }      
    }

Fragment of my file(.txt):我的文件片段(.txt):

 13:37 Kill: 3 4 7: Oootsimo killed Dono da Bola by MOD_ROCKET_SPLASH
 13:37 Item: 5 weapon_rocketlauncher
 13:39 Item: 6 weapon_rocketlauncher
 13:40 Item: 7 ammo_rockets
 13:41 Item: 6 weapon_rocketlauncher
 13:41 Item: 4 weapon_rocketlauncher
 13:43 Kill: 2 5 6: Isgalamido killed Assasinu Credi by MOD_ROCKET
 13:45 Kill: 1022 7 22: <world> killed Mal by MOD_TRIGGER_HURT
 13:46 Kill: 4 3 7: Dono da Bola killed Oootsimo by MOD_ROCKET_SPLASH
 13:46 Kill: 6 2 6: Zeh killed Isgalamido by MOD_ROCKET

I don't know all of your requirements, but try using Regexp:我不知道您的所有要求,但请尝试使用 Regexp:

@Test
public void test()
{
    String string = "13:46 Kill: 6 2 6: Zeh killed Isgalamido by MOD_ROCKET";
    String regexp = "\\d+:\\d+ .*?([A-Za-z0-9]+) killed ([A-Za-z0-9]+).*?";
    String player1 = null;
    String player2 = null;

    Pattern p = Pattern.compile(regexp);

    Matcher m = p.matcher(string);

    if (m.find())
    {
        player1 = m.group(1);
        player2 = m.group(2);
    }

    assertEquals("Zeh", player1);
    assertEquals("Isgalamido", player2);
}

Explanation: \\d+ - A digit, one or more times说明:\\d+ - 一个数字,一次或多次

.* - Any character, any number of times. .* - 任意字符,任意次数。 the '?'这 '?' means 'non greedy', so characters matching the following expression won't be overaken表示“非贪婪”,因此匹配以下表达式的字符不会被覆盖

([A-Za-z0-9]+) - character ranges inside the '[]', one or more times, captured ([A-Za-z0-9]+) - '[]' 内的字符范围,一次或多次,被捕获

I'll edit my answer again once I can confirm this is what you meant一旦我确认这是你的意思,我会再次编辑我的答案

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