二进制运算符'=='不能应用于'NSObject'和'String'类型的操作数

Question

I am trying to search users on a UITableView, through a UISearchBar. The thing is that an error keeps appearing when I try to.

Here's my code:

 var isSearching = false
 func searchBar(_ searchBar: UISearchBar, textDidChange searchText:String) {
     if searchBar.text == nil || searchBar.text == "" {
        isSearching = false
        view.endEditing(true)
        searchTableView.reloadData()
    } else {
        isSearching = true
        filteredUsers = users.filter({$0 == searchBar.text!})  // error appears here

    }

    searchTableView.reloadData()
}

I am trying to search for the users in my app, through Firebase fetch. I've already fetched the users onto a UITableView, the thing is I cant search for a specific one. Please help! I've tried everything.

Answer 1

A type NSObject can't compared with a type of String , you need

filteredUsers = users.filter({$0.someProperty == searchBar.text!}) 

where someProperty is a property inside the class