[英]Problem with pagination in template django?
I have such view in my application and I try to paginate in in my temlate. 我在应用程序中有这样的观点,并尝试在我的模板中进行分页。 But prev and next don't work. 但是上一个和下一个不起作用。 What's wrong? 怎么了?
class ForMenView(ListView):
model = Post
template_name = 'man_index.html'
context_object_name = 'all_posts'
paginate_by = 1
def get_queryset(self):
query = self.request.GET.get('q')
qs = Post.objects.filter(sex='M', is_published=True)
if query:
return qs.filter(title__icontains=query)
return qs
def get_paginate_by(self, queryset):
user = self.request.user
if user.is_authenticated and user.sex == 'M':
return 1
return self.paginate_by
def dispatch(self, request, *args, **kwargs):
user = self.request.user
if user.is_authenticated and user.sex == 'W':
return redirect('/forwomen') # please replace it with the view name
else:
return super(ForMenView, self).dispatch(self.request ,*args, **kwargs)
def get_context_data(self, *args, **kwargs):
kwargs = super(ForMenView, self).get_context_data(*args, **kwargs)
kwargs['page_range'] = kwargs['paginator'].page_range
return kwargs
And in my template I try to paginate such way 在我的模板中,我尝试以这种方式进行分页
THIS DOESN'T DISPLAY AT ALL
{% if all_posts.has_previous %}
<li><a class="pgn__prev" href="?page={{ all_posts.previous_page_number }}">Prev</a></li>
{% endif %}
{% for x in page_range %}
<li><a class="pgn__num" href="?page={{ x }}">{{ x }}</a></li>
{% endfor %}
THIS DOESN'T DISPLAY TOO
{% if all_posts.has_next %}
<li><a class="pgn__next" href="?page={{ all_posts.next_page_number }}">Next</a></li>
{% endif %}
My context value of {{all_posts}} = <[Post: TitlePost]> Why dont previous and next work? 我的{{all_posts}}上下文值= <[Post:TitlePost]>为什么上一个和下一个无效?
all_posts
is just queryset. all_posts
只是queryset。 To check previous and next page you need page
object, which passed to the template as page_obj
variable: 要检查上一页和下一页,您需要page
对象,该对象作为page_obj
变量传递到模板:
{% if page_obj.has_previous %}
<li><a class="pgn__prev" href="?page={{ page_obj.previous_page_number }}">Prev</a></li>
{% endif %}
{% if page_obj.has_next %}
<li><a class="pgn__next" href="?page={{ page_obj.next_page_number }}">Next</a></li>
{% endif %}
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