[英]How to change a list of list to a dictionary of dictionary?
So for example I have the following list of lists因此,例如我有以下列表列表
A = [['PokedexNumber', 'Name', 'Type', 'Total'], [1.0, 'Bulbasaur', 'GrassPoison', 318.0], [2.0, 'Ivysaur', 'GrassPoison', 405.0],[3.0, 'Venusaur', 'GrassPoison', 525.0]]
How do i change it to dictionary of dictionaries?我如何将其更改为字典字典?
B = { 1.0 : { 'Name' : 'Bulbasaur', 'Type' : 'GrassPoison', 'Total' : 318.0},
2.0 : {'Name' : 'Ivysaur', 'Type' : 'GrassPoison', 'Total' : 405.0},
3.0 : {'Name' : 'Venusaur', 'Type' : 'GrassPoison', 'Total' : 525.0}
}
You can use sequence unpacking and a dictionary comprehension:您可以使用序列解包和字典理解:
(_, *headers), *data = A
res = {num: dict(zip(headers, values)) for num, *values in data}
Result:结果:
{1.0: {'Name': 'Bulbasaur', 'Type': 'GrassPoison', 'Total': 318.0},
2.0: {'Name': 'Ivysaur', 'Type': 'GrassPoison', 'Total': 405.0},
3.0: {'Name': 'Venusaur', 'Type': 'GrassPoison', 'Total': 525.0}}
Try this:尝试这个:
>>> A = [['PokedexNumber', 'Name', 'Type', 'Total'], [1.0, 'Bulbasaur', 'GrassPoison', 318.0], [2.0, 'Ivysaur', 'GrassPoison', 405.0],[3.0, 'Venusaur', 'GrassPoison', 525.0]]
>>> B = {}
>>> for p in A[1:]:
... B[p[0]] = { 'name': p[1], 'type': p[2], 'total': p[3] }
...
>>> B
{1.0: {'total': 318.0, 'type': 'GrassPoison', 'name': 'Bulbasaur'}, 2.0: {'total': 405.0, 'type': 'GrassPoison', 'name': 'Ivysaur'}, 3.0: {'total': 525.0, 'type': 'GrassPoison', 'name': 'Venusaur'}}
>>>
Here's a dictionary comprehension with slicing that should do the trick:这是一个带有切片的字典理解,应该可以解决问题:
A = [['PokedexNumber', 'Name', 'Type', 'Total'], [1.0, 'Bulbasaur', 'GrassPoison', 318.0], [2.0, 'Ivysaur', 'GrassPoison', 405.0],[3.0, 'Venusaur', 'GrassPoison', 525.0]]
B = {x[0]: dict(zip(A[0][1:], x[1:])) for x in A[1:]}
print(B)
Output:输出:
{
1.0: {'Name': 'Bulbasaur', 'Type': 'GrassPoison', 'Total': 318.0},
2.0: {'Name': 'Ivysaur', 'Type': 'GrassPoison', 'Total': 405.0},
3.0: {'Name': 'Venusaur', 'Type': 'GrassPoison', 'Total': 525.0}
}
If you are happy to use a 3rd party library, you can use Pandas:如果您乐于使用 3rd 方库,则可以使用 Pandas:
import pandas as pd
headers, *data = A
df = pd.DataFrame(data, columns=headers)
B = df.set_index('PokedexNumber').to_dict('index')
Result:结果:
{1.0: {'Name': 'Bulbasaur', 'Type': 'GrassPoison', 'Total': 318.0},
2.0: {'Name': 'Ivysaur', 'Type': 'GrassPoison', 'Total': 405.0},
3.0: {'Name': 'Venusaur', 'Type': 'GrassPoison', 'Total': 525.0}}
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