[英]Pandas Data Frame conditional flow with multiple columns
I have a data frame as follow: 我有一个数据框如下:
fix = pd.DataFrame()
fix ['Home'] =['A','B','C','D','E']
fix ['Away'] =['F','G','H','I','J']
fix ['GD = -2'] = [0.2,0.3,0.5,0.1,0.6]
fix ['GD = -1'] = [0.25,0.1,0.55,0.35,0.43]
fix ['GD = 0'] = [0.1,0.2,0.23,0.5,0.4]
fix ['GD = 2'] = [0.1,0.5,0.2,0.12,0.18]
fix ['GD = 1'] = [0.24,0.5,0.33,0.31,0.13]
I want to create a new column that contain the winning team based on GD (ie GD +ve means Home will win, GD -Ve means Away will win, GD = 0 means draw. 我想创建一个包含基于GD的获胜团队的新列(即GD + ve表示主场获胜,GD -Ve表示客队获胜,GD = 0表示平局。
so I wrote the following code to workout the new column. 所以我写了下面的代码来锻炼新的专栏。
GDPlus = fix ['GD=1'] or fix['GD=2']
GDMins = fix ['GD= -1'] or fix['GD= -2']
fix['Winning_Team'] = np.select([GDPlus,GDMins],[fix.Home,fix.Away],default ='Draw')
It threw me an error as follow: 它使我犯了如下错误:
ValueError: The truth value of a Series is ambiguous. Use a.empty, a.bool(), a.item(), a.any() or a.all().
Could anyone advise how to do that? 有人可以建议如何做吗?
If want new column by max
value: 如果要通过
max
新列:
#get max values per rows
smax = fix.max(axis=1)
compare by eq (==) and check if at least one True per rows
GDPlus = fix[['GD = 1','GD = 2']].eq(smax, axis=0).any(axis=1)
GDMins = fix[['GD = -1','GD = -2']].eq(smax, axis=0).any(axis=1)
Your solution should be changed by comparing by eq
( ==
): 您的解决方案应通过比较
eq
( ==
)来更改:
GDPlus = fix ['GD = 1'].eq(smax) | fix['GD = 2'].eq(smax)
GDMins = fix ['GD = -1'].eq(smax) | fix['GD = -2'] .eq(smax)
#alternative solution
#GDPlus = (fix['GD = 1'] == smax) | (fix['GD = 2'] == smax)
#GDMins = (fix['GD = -1'] == smax) | (fix['GD = -2'] == smax)
fix['Winning_Team'] = np.select([GDPlus,GDMins],[fix.Home,fix.Away],default ='Draw')
print (fix)
Home Away GD = -2 GD = -1 GD = 0 GD = 2 GD = 1 Winning_Team
0 A F 0.2 0.25 0.10 0.10 0.24 F
1 B G 0.3 0.10 0.20 0.50 0.50 B
2 C H 0.5 0.55 0.23 0.20 0.33 H
3 D I 0.1 0.35 0.50 0.12 0.31 Draw
4 E J 0.6 0.43 0.40 0.18 0.13 J
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