[英]Dataframe R, add every other row
This brief example illustrates the problem. 这个简短的例子说明了这个问题。 I want to add the same information Total
and Value
after every row in my dataframe. 我想在数据框中的每一行之后添加相同的信息Total
和Value
。 The correct ID
should be given to every new row. 正确的ID
应该分配给每个新行。
data.frame(ID=c('A1','A2'), one=c(1,2), two=c(3,4))
ID one two
1 A1 1 3
2 A2 2 4
The final results should look like this. 最终结果应如下所示。
data.frame(ID=c('A1','A1','A2','A2'), one=c(1,'Total',2,'Total'), two=c(3,'Value',4,'Value'))
ID one two
1 A1 1 3
2 A1 Total Value
3 A2 2 4
4 A2 Total Value
I found a few related SO questions, but they don't really answer my question. 我发现了一些相关的SO问题,但它们并没有真正回答我的问题。
I'm a bit curious about the usefulness of such a transformations, but this is one way to accomplish it: 我对这种转换的用途有些好奇,但这是完成转换的一种方式:
df <- data.frame(ID=c('A1','A2'), one=c(1,2), two=c(3,4))
library(tidyverse)
df %>%
mutate(one='Total', two='Value') %>%
bind_rows(mutate_all(df, as.character)) %>%
arrange(ID, one)
Output: 输出:
ID one two
1 A1 1 3
2 A1 Total Value
3 A2 2 4
4 A2 Total Value
A base R version would be 基本的R版本是
#Create a new dataframe with same rows with `ID` value from df
df1 <- data.frame(ID = df$ID, one='Total', two='Value')
#rbind both the dataframes
df2 <- rbind(df, df1)
#Order the new dataframe based on the ID to get alternating rows
df2[order(df2$ID), ]
# ID one two
#1 A1 1 3
#3 A1 Total Value
#2 A2 2 4
#4 A2 Total Value
data 数据
df <- data.frame(ID=c('A1','A2'), one=c(1,2), two=c(3,4))
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