如何在 iOS 11+ 中以编程方式打开设置 > 隐私 > 定位服务？

Question

If locationServicesEnabled return false, I'm prompting the user to enable their Location Services. The following URL works for 10.0+, redirecting the user to the Settings app and directly to the Location Services screen:

URL(string: "App-Prefs:root=Privacy&path=LOCATION")

However this doesn't work in iOS 11. It opens the Settings app, but doesn't drill down to the Location Services. Anyone knows what's the new URL for iOS 11+?

Answer 1

Apple published a list of URLs which they explicitly allow at this link . Unfortunately if you use other URLs (such as the one you are trying to use) this can get your app rejected from the App Store.

Short answer: You cannot do what you are trying to do without breaking the App Store rules.

Answer 2

Use this-

UIApplication.shared.open(URL(string:UIApplicationOpenSettingsURLString)!)

Using App-prefs may lead to the rejection of the app on app store.

Or you can try this also-

if let bundleId = Bundle.main.bundleIdentifier,
let url = URL(string: "\(UIApplication.openSettingsURLString)&path=LOCATION/\(bundleId)") {
    UIApplication.shared.open(url, options: [:], completionHandler: nil)
}

Answer 3

In iOS 15 this wasn't working for me, as it was just opening the general settings page, but based on shivi_shub answer and his comment I tried the following:

if let bundleId = Bundle.main.bundleIdentifier,
   let url = URL(string: "\(UIApplication.openSettingsURLString)&path=LOCATION_SERVICES/\(bundleId)")
{
    UIApplication.shared.open(url, options: [:], completionHandler: nil)
}

And it brought me to the location settings, which at least is a couple steps closer to the settings page I really want to show.

So I guess we could just do:

if let url = URL(string: "\(UIApplication.openSettingsURLString)&path=LOCATION_SERVICES") {
    UIApplication.shared.open(url, options: [:], completionHandler: nil)
}