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C ++中的按位运算符和重载

[英]Bitwise operators in c++ and overloading

I have written some code to print the value of an integer raised to an integer power. 我已经写了一些代码来打印一个整数值,该整数值被提高为整数幂。 Why does this code pause for input even after I have entered 2 integers? 为什么即使我输入了2个整数,该代码也会暂停输入?

#include<iostream>

int main(){
    int a, b;
    std::cin>>a>>b;
    std::cout<<std::endl<<a<<std::endl<<b<<std::endl;
    int c, d;
    c = a;
    d = 0;
    while(b){
        if(b&1)
            d += c;
        if(b>>1){
            b = b>>1;
            c *= c;
        }
    }

    std::cout<<d;
    return 0;
}

I suspected that the compiler misinterprets the bitwise operator as an overloaded operator, but even if I change the condition in the while loop to 我怀疑编译器将按位运算符误解为重载运算符,但是即使我将while循环中的条件更改为

if(b/2 > 0){
    b = b/2;
    c *= c;
}

it still doesn't work. 它仍然不起作用。 I have no idea what is going on here. 我不知道这是怎么回事。 I've tried this code in the terminal, and some online IDEs, but the result is the same. 我已经在终端和一些在线IDE中尝试了此代码,但是结果是相同的。

std::cin>>a>>b; is grouped as (std::cin>>a)>>b; 分组为(std::cin>>a)>>b; so be assured that two integers are read. 因此请确保读取两个整数。

Your problem is that the program loops if b is anything other than 0. 您的问题是,如果b为0以外的任何值,程序就会循环执行。

As noted, you never assign a 0 value to b, so the loop never ends. 如前所述,您永远不会为b分配0值,因此循环永远不会结束。 You can replace the if test with something that does the assignment. 您可以将if测试替换为执行赋值的操作。

if(b >>= 1)
    c *= c;

I prefer this to b = b >> 1 as it is more obvious you mean to assign, and don't mean to compare b == b >> 1 我更喜欢b = b >> 1 ,因为更明显的是您要分配,而不是要比较b == b >> 1

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