调用（标记）将任务作为异步返回的方法是否正确

Question

I have methods provided by the database driver that pushes a value to db (both async and non-async) like so,

pushToDBAsync(); and pushToDB();

So I created a wrapper method for the driver methods for my own implementation shown below. Is this correct? and also Is it right to call this an async method?

public Task<bool> pushToDBAsync(.....)
{
    return _database.pushToDBAsync(.....);
}

Answer 1

This is an async method as the caller can await it. The difference with using
public async Task<bool> pushToDBAsync(....)
is that you give the caller the capability to decide how to handle the Task. Doing in that way may also help avoiding some pitfalls as mentioned in this blogpost: http://blog.stephencleary.com/2016/12/eliding-async-await.html

Long story short: Labeling such a method with Async communicates the caller that it can be awaited and makes it easier to interact with your code.

Answer 2

*If you want to use your method as a pushToDBAsync(); so you follow below code for method syntax.

public Async Task<bool> pushToDBAsync(.....)
{
return await _database.pushToDBAsync(.....);
}

*If you want to use your method as a pushToDB(); So you follow below code for method syntax.

public Task<bool> pushToDBAsync(.....)
{
  return _database.pushToDBAsync(.....);
 // Return same but execution time more compare than Async method.
 }