如何显示带有换行符的从oracle数据库获取的JSON输出

Question

I have an HTML page which is has one user input and one button. After clicking on the button, we can fetch other data related to that user from oracle database. i have defined my code in a seperate php page( index2.php ) which looks like below:-

<?php
class logAgent
{
    const CONFIG_FILENAME = "data_config.ini";

    private $_dbConn;
    private $_config;


    function __construct()
    {
        $this->_loadConfig();


        $this->_dbConn = oci_connect($this->_config['db_usrnm'],
            $this->_config['db_pwd'],
            $this->_config['hostnm_sid']);
    }
    private function _loadConfig()
    {
        // Loads config
        $path = dirname(__FILE__) . '/' . self::CONFIG_FILENAME;
        $this->_config = parse_ini_file($path) ;
    }
    public function fetchLogs() {
        $userid =$_POST["userid"];
        $sql = "SELECT REQUEST_TIME,WORKFLOW_NAME,EVENT_MESSAGE
                            FROM AUTH_LOGS WHERE USERID = '".$userid."'";
        //Preparing an Oracle statement for execution
        $statement = oci_parse($this->_dbConn, $sql);

        //Executing statement
        oci_execute($statement);
        $json_array = array(); 

        while (($row = oci_fetch_row($statement)) != false) {
            $rows[] = $row;
            $json_array[] = $row; 
        }
            echo json_encode($json_array);
    }

}
    $logAgent = new logAgent();
    $logAgent->fetchLogs();
?>

I am doing this using asynchronous post method my defining a javascript file(script.js)

 $(document).ready(function(){ $("#mybtn").click(function(e){ e.preventDefault(); var userid = $("#userid").val(); //$.post("index2.php", {"userid" : userid}) var posting = $.post( 'index2.php', {"userid" : userid}); posting.done(function( res ) { var response = $.parseJSON(res); $('#rawResponse').text(response); }); }); }) 

I have many data for one user. And output display looks like: 03-SEP-18,softOtpCheck,OTP check passed,03-SEP-18,createAuthenticatedSession,yoya session Created.,03-SEP-18,createAuthenticatedSession,yoya session Created.,03-SEP-18,oamAuth,OAM context cookie collected.,03-SEP-18,softOtpCheck,OTP check passed,03-SEP-18,createAuthenticatedSession,yoya session Created.,03-SEP-18,createAuthenticatedSession,yoya session Created.,03-SEP-18,oamAuth,OAM context cookie collected.

But i want it as :

03-SEP-18,softOtpCheck,OTP check passed,

03-SEP-18,createAuthenticatedSession,yoya session Created.,

03-SEP-18,createAuthenticatedSession,yoya session Created.,

03-SEP-18,oamAuth,OAM context cookie collected.,

03-SEP-18,softOtpCheck,OTP check passed,

03-SEP-18,createAuthenticatedSession,yoya session Created.,

03-SEP-18,createAuthenticatedSession,yoya session Created.,

03-SEP-18,oamAuth,OAM context cookie collected.

How can i display my output in a newline?

Answer 1

如果要回显json数据，则可以使用JSON_PRETTY_PRINT返回带有换行符的美化数据。

echo json_encode($json_array, JSON_PRETTY_PRINT);

Answer 2

I believe you want to change

$('#rawResponse').text(response);

to

$('#rawResponse').html('<pre>' + JSON.stringify(response, null, 2) + '</pre>);

See JSON.stringify and the enclosing pre tags will display the return value nicely. Alternatively you could also put it into a textarea , it will also display the newlines properly.