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发布请求等待功能

[英]Post request to wait a function

I know the question is asked really often, and I might get downvoted for that. 我知道这个问题经常被问到,我对此可能会感到失望。 But I really struggle to understand how I can wait for a function to process data before returning a value. 但是我真的很难理解如何在返回值之前如何等待函数处理数据。

I had a look on many popular posts (such as here ), but I cannot achieve what I want. 我浏览了许多受欢迎的帖子(例如here ),但无法实现自己想要的功能。

Here is my code: 这是我的代码:

   app.post("/video_url", function (req, res) {
       videoProcessed = videoScraper(req.body.videoURL.videoURL);
       res.send(videoProcessed);
   });

It does not wait for this function to process the data: 它不等待此函数处理数据:

function videoScraper(url) {
console.log("URL to Scraper: " + url);
const options = {
    uri: `${url}`,
    transform: function(body) {
        return cheerio.load(body);
    }
};

var videoProcessed;

rp(options)
    .then(($) => {
        videoProcessed = $("body").find("iframe").attr("src");
        return videoProcessed;
    })
    .catch((err) => {
        console.log(err);
    });
}

I tried using callbacks but it gets really messy, and I don't know were to put the promise (if any) in my code. 我尝试使用回调,但是它确实很混乱,而且我不知道是否要在代码中放入promise(如果有)。

Add await and async (if you have node 8+): 添加等待和异步(如果您的节点为8+):

app.post("/video_url", async function (req, res) {
    const videoProcessed = await videoScraper(req.body.videoURL.videoURL);
    res.send(videoProcessed);
});

And in your videoScraper function, you need to return rp ! videoScraper函数中,您需要返回rp :

function videoScraper(url) {
    console.log("URL to Scraper: " + url);
    const options = {
        uri: `${url}`,
        transform: function(body) {
            return cheerio.load(body);
        }
    };

    return rp(options)
    .then($ => $("body").find("iframe").attr("src"))
    .catch((err) => {
        console.error(err);
    });
}

That would depend on the videoScrapper working fine, I've no idea what rp is so I can't tell. 那将取决于videoScrapper工作正常,我不知道rp是什么,所以我无法分辨。

Don't forget to handle videoProcessed === undefined (error case) in the first code snippet. 不要忘记在第一个代码片段中处理videoProcessed === undefined (错误情况)。 It can also be abstracted using express-promise-router that will even catch async errors... That's further down the road. 还可以使用express-promise-router对其进行抽象,该express-promise-router甚至会捕获异步错误...进一步的发展。

Don't hesitate to read up on await & async, it's really wonderful to write asynchronous code in the same manner as synchronous code. 不要犹豫,在等待和异步上进行读取,以与同步代码相同的方式编写异步代码真的很棒。

Use async/await 使用异步/等待

app.post("/video_url", async (req, res)=> {
try{
    let videoProcessed = await videoScraper(req.body.videoURL.videoURL);
    res.send(videoProcessed);
}
catch(ex){
// handle the exception
}
});

const videoScraper = async fuction(url) {
console.log("URL to Scraper: " + url);
let options = {
    uri: `${url}`,
    transform: function(body) {
        return cheerio.load(body);
    }
};
try{
let temp = await rp(options);
let videoProcessed = $("body").find("iframe").attr("src");// you can return it directly
return videoProcessed;
}
catch(ex){
// handle the exception
}
}

if you your node is < 8 then use promises ( bluebird module) 如果您的节点小于8,则使用promises( bluebird模块)

const bluebird = require('bluebird');
function videoScraper(url){
return new bluebird(function(resolve,reject){
let options = {
    uri: `${url}`,
    transform: function(body) {
        return cheerio.load(body);
    }
};
rp(options)
.then(($)=>{
resolve($("body").find("iframe").attr("src"));
})
.catch(err=>{
return err;
})
})
}
app.post("/video_url", (req, res)=> {
videoScraper(req.body.videoURL.videoURL)
.then(result=>{
res.send(result)
})
.catch(err=>{
// handle the error
})
});

Do not use const for variable declaration unless its value is constant, and usually use let instead of var 除非其值是常量,否则不要将const用于变量声明,并且通常使用let而不是var

You can try the following: 您可以尝试以下方法:

app.post("/video_url", function (req, res) {
    videoScraper(req.body.videoURL.videoURL)
        .then(videoProcessed => {
            res.send(videoProcessed);
        })
        .catch(err => {
            // render proper response with error message
        })
});

And change the function to something as below, so as to return a promise from the same: 并将函数更改为以下内容,以从中返回promise:

function videoScraper(url) {
    console.log("URL to Scraper: " + url);
    const options = {
        uri: `${url}`,
        transform: function(body) {
            return cheerio.load(body);
        }
    };

    return rp(options)
        .then(($) => {
            videoProcessed = $("body").find("iframe").attr("src");
            return videoProcessed;
        });
}

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