[英]Angular Firestore Get Single Document With Query
I'm using Google Firestore. 我正在使用Google Firestore。 There is a collection called Universities, where each document represents a university.
有一个名为Universities的集合,每个文档代表一所大学。
How do I find a university by its name and update its view_count by +1? 如何按名称查找大学并将其view_count更新为+1?
[Collection: Universities]:
[Document: 0JsaLtcfdDaEtHLMlMrh]:{
name: The University of Sydney,
view_count: 1
};
[Document: K2z7DMhKreyDniGUpo2t]:{
name: University of New South Wales,
view_count: 2
}
You can do something like this: 你可以这样做:
db.collection("Universities").where("name", "==", "The University of Sydney")
.get()
.then(function(querySnapshot) {
querySnapshot.forEach(function(doc) {
// doc.data() is never undefined for query doc snapshots
//console.log(doc.id, " => ", doc.data());
var docData = doc.data();
var updatedCount = docData.view_count + 1;
var universityRef = db.collection('Universities').doc(doc.id);
var setWithMerge = universityRef.set({
view_count: updatedCount
}, { merge: true });
});
})
.catch(function(error) {
console.log("Error getting documents: ", error);
});
So, here what you can do is first query in collection using where
to get all docs with specific name, then inside querySnapshot
you'll get one doc object & then you can create reference of that document & update (overwrite) its view_count
property value using set
method with merge: true
to keep other property values as it's. 所以,这里你可以做的是首先在集合中查询使用
where
获取具有特定名称的所有文档,然后在querySnapshot
你将获得一个doc对象然后你可以创建该文档的引用并更新(覆盖)其view_count
属性值使用带有merge: true
set
方法merge: true
来保持其他属性值。
Follow offcial docs: Add data , Get data 关注官方文档: 添加数据 , 获取数据
Note: This's generic web JS solution. 注意:这是一般的Web JS解决方案。 You can use same logic & write typescript code in angular app
您可以在角度应用程序中使用相同的逻辑和编写打字稿代码
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