Javascript数组在不知道父键的情况下获取所有子值

Question

I would like to validate and check if there is any existing object with true value where I don't know how to directly access all child exist value without having me to loop through the parent array. Below show the result.

{
 user1: Array(2)
  0: {exist: false}
  1: {exist: true}
 user2: Array(2)
  0: {exist: false}
  1: {exist: false}
}

Answer 1

If you know the object will only be this deep, you can use some on Object.values() . You are still looping through the arrays — there's no way to avoid that — but at least it's fairly succinct:

 let obj = { user1:[ {exist: false}, {exist: false} ], user2: [ {exist: false}, {exist: true} ] } let t = Object.values(obj).some(arr => arr.some(o => o.exist === true)) // are some objects true? console.log(t) 

If your objects can be arbitrarily deep, you will need to recursively look at everything.

Answer 2

You cannot. You either query parent key, then child key, or you loop all the parent keys, then child keys.