电子邮件的Javascript正则表达式，允许在电子邮件中使用“ \\”

Question

I have a regex for my email:

const EMAIL = /^(([^<>()\[\].,;:\s@\"]+(\.[^<>()\[\]\.,;:\s@\"]+)*)|(\".+\"))@(([^<>()[\]\.,;:\s@\"]+\.)+[^<>()[\]\.,;:\s@\"]{2,})$/i;

I want to validate below email as true:

Fred\ Bloggs@example.com true
Joe.\\Blow@example.com true
""test\\blah""@example.com true

Below email as false: ""test\\blah""@example.com

currently, I'm not able to do this validation please help

Answer 1

 function validateEmail(email) { var re = /(([^<>()\\[\\].,;:\\s@\\"]+(\\.[^<>()\\[\\]\\.,;:\\s@\\"]+)*)|(\\".+\\"))@(([^<>()[\\]\\.,;:\\s@\\"]+\\.)+[^<>()[\\]\\.,;:\\s@\\"]{2,})$/i; return re.test(String(email).toLowerCase()); } var test_email1 ='""test\\blah""@example.com"'; alert(validateEmail(test_email1)); var test_email2 ='Fred\\ Bloggs@example.com'; alert(validateEmail(test_email2)); var test_email3 ='Joe.\\\\Blow@example.com'; alert(validateEmail(test_email3)); var test_email4 ='""test\\\\blah""@example.com'; alert(validateEmail(test_email4)); 

Answer 2

Here is the function from Omid's answer using a regex that meets RFC 2822 .

function validateEmail(email) {
    var re = /(?:[a-z0-9!#$%&'*+/=?^_`{|}~-]+(?:\.[a-z0-9!#$%&'*+/=?^_`{|}~-]+)*|"(?:[\x01-\x08\x0b\x0c\x0e-\x1f\x21\x23-\x5b\x5d-\x7f]|\\[\x01-\x09\x0b\x0c\x0e-\x7f])*")@(?:(?:[a-z0-9](?:[a-z0-9-]*[a-z0-9])?\.)+[a-z0-9](?:[a-z0-9-]*[a-z0-9])?|\[(?:(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.){3}(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?|[a-z0-9-]*[a-z0-9]:(?:[\x01-\x08\x0b\x0c\x0e-\x1f\x21-\x5a\x53-\x7f]|\\[\x01-\x09\x0b\x0c\x0e-\x7f])+)\])/;
    return re.test(String(email).toLowerCase());
}

console.log(validateEmail('Fred\ Bloggs@example.com')); // logs true
console.log(validateEmail('Joe.\\Blow@example.com')); // logs true
console.log(validateEmail('""test\\blah""@example.com')); // logs true

You'll notice this function doesn't return false on the case you'd like to fail.

The only way to really test an email address is to send an email to it -- don't rely on regex to verify email addresses because your regex will never be perfect.