Python将*未知格式的字符串解析为json或dict

Question

The reason I say unknown is because it is being sent from an IOS 12 extension, I have no-hand in creating this format but lets just suppose there is no way I can do any formatting over there.

In Python what I receive is a string in the following format:

 {
   "body": '{\n  carrierName = "AT&T";\n dateRecieved = "2018-08-07 20:29:56 +0000";\n \n}'
 }

I want to know what this format {foo="bar"; top="long";} is called? It is what gets returned from iOS native Libraries so it has to be something; And is there any built-in way to parse it as a json or a dict. I can write my own parser for sure, but im looking for something built-in or something that exist in some generic library.

Answer 1

What you have in the dictionary looks like JavaScript. Fortunately, Python can interpret JS via py_mini_racer . Install the module (say, with pip ), create an instance of the interpreter:

from py_mini_racer import py_mini_racer
js = py_mini_racer.MiniRacer()

d = {
   "body": '{\n  carrierName = "AT&T";\n dateRecieved = "2018-08-07 20:29:56 +0000";\n \n}'
 }

Evaluate the expression and the variables, as needed:

js.eval(d['body'])
js.eval("carrierName")
#'AT&T'
js.eval("dateRecieved")
#'2018-08-07 20:29:56 +0000'

Answer 2

parsing without the py_mini_racer. I could not install py_mini_racer on my
python 3.7

d = {
   "body": '{\n  carrierName = "AT&T";\n dateRecieved = "2018-08-07 20:29:56 +0000";\n \n}'
 }  

def parseD(d):
    import re
    def makeD(l): # make dict from 2 element list
        return dict([[s.strip().replace('"','') for s in l]])
    finalD = {}
    for di in [makeD(x) for x in [s.split('=') for s in re.findall(r'(\w+\s+=.*);', list(d.values())[0])]]:
        finalD.update(di)
    return finalD

parseD(d)   

{'carrierName': 'AT&T', 'dateRecieved': '2018-08-07 20:29:56 +0000'}

d = parseD(d)

d['carrierName']  

'AT&T'

d['dateRecieved']

'2018-08-07 20:29:56 +0000'