[英]Return python string as the body of HTTP response
I am using AWS Lambda
with python-2.7
replying back to AWS Api Gateway
. 我正在将
AWS Lambda
与python-2.7
回复AWS Api Gateway
。 My lambda function should return a response looking like following, but I am strugling with putting the proper form of body in the JSON response: 我的lambda函数应该返回如下所示的响应,但是我正在努力将正确的body形式放入JSON响应中:
return_value = {
"statusCode": 200,
"isBase64Encoded": 'false',
"headers": {"Content-Type": "application/json"},
"body": {payload['note']}
}
the type of payload['note']
is unicode
, so I don't know what exactly to put in the brackets opposite to body
, as I am new to python and tried a lot without being able to figure it out. payload['note']
的类型是unicode
,所以我不知道在body
对面的括号中到底放什么,因为我是python的新手,并且尝试了很多却无法弄清楚。 I tried to convert it to string using: 我试图使用以下方法将其转换为字符串:
unicodedata.normalize('NFKD', payload['note']).encode('ascii', 'ignore')
But it didn't work either. 但这也不起作用。
First, I believe it is a good idea to convert the unicode string to a python string before, since I dont know if the rest of your code can handles unicode in json. 首先,我认为将unicode字符串转换为python字符串是一个好主意,因为我不知道您的其余代码是否可以处理json中的unicode。
I think your problem is related to json formatting. 我认为您的问题与json格式有关。 As JSON, the body field should contain key-value pairs.
作为JSON,主体字段应包含键值对。
Try with : 尝试:
return_value = {
"statusCode": 200,
"isBase64Encoded": 'false',
"headers": {"Content-Type": "application/json"},
"body": {"note": payload['note']}
}
It's probably best to build it using standard objects first, then convert it to JSON as you return it. 最好先使用标准对象进行构建,然后在返回时将其转换为JSON。 For example:
例如:
# coding=utf-8
import json
def aws_message(payload):
message = dict(statusCode=200,
isBase64Encoded=False,
headers={"Content-Type": "application/json"},
body=payload['note'])
return json.dumps(message)
if __name__=="__main__":
payload = dict(note='something')
print(aws_message(payload))
Unfortunately you'll notice I switched from the long-form dict() creation to the short-hand when building the headers inside the message (it was a quick 'n dirty example). 不幸的是,您会在构建消息内的标头时从长格式的dict()创建切换为简写形式(这是一个快速的'n肮脏示例)。 Here is the output:
这是输出:
C:\Python37\python.exe C:/dev/scratches/scratch_17.py
{"statusCode": 200, "isBase64Encoded": false, "headers": {"Content-Type": "application/json"}, "body": "something"}
As you can see, it's quite straight-forward to build the object in a fashion that is easy to understand, and then let the json library do all the conversion into a correctly-formatted response. 如您所见,以一种易于理解的方式构建对象,然后让json库将所有转换全部转换为格式正确的响应是非常简单的。 I hope this helps.
我希望这有帮助。
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