如何列出目录中的文件并逐一处理？ -Python

Question

i want to make a list of all text files in a directory. then i want to create separate list of the contents in each file. eg document1=[] and then document2=[] so on. and then by using document 1 and document 2 keywords i want to calculate term frequency and other processes. code is running but list cant be assigned different names as document1 and so on.

import glob
import math
import re

a=0
flist=glob.glob(r'D:/Final Year Project/Development process/Text_data_extraction/MyFolder/*.txt') #get all the files from the d`#open each file >> tokenize the content >> and store it in a set
for fname in flist:         
    tfile=open(fname,"r")
    line=tfile.read()
    a+=1
    line = line.lower() # lowercase
    line = re.sub("</?.*?>"," <> ",line) #remove tags
    line = re.sub("(\\d|\\W)+"," ",line)  # remove special characters and digits
    l_ist = line.split("\n")
    print 'document'
    print(l_ist)
tfile.close() # close the file
print"Number of documents:"
print(a)

Answer 1

You can assign the list you create in each iteration to a dict indexed by the file name:

import glob
import math
import re

flist=glob.glob(r'D:/Final Year Project/Development process/Text_data_extraction/MyFolder/*.txt') #get all the files from the d`#open each file >> tokenize the content >> and store it in a set
content = {}
for fname in flist:         
    tfile=open(fname,"r")
    line=tfile.read()
    line = line.lower() # lowercase
    line = re.sub("</?.*?>"," <> ",line) #remove tags
    line = re.sub("(\\d|\\W)+"," ",line)  # remove special characters and digits
    l_ist = line.split("\n")
    print 'document'
    print(l_ist)
    content[fname] = l_lst
tfile.close() # close the file
print("Number of documents:")
print(len(content))
print(content) # to verify the content of the entire dict

Answer 2

转到这里 ，我相信不要仅仅给出文本文件名，而要给出目录路径以及名称结构，对于“ document1，document2 ...”，请使用循环，或者如果设置了文件文件数，请使用它们。