熊猫：Bin的日期间隔为30分钟并计算平均值

Question

I have a Pandas dataframe with two columns which are speed and time .

speed   date
54.72   1:33:56
49.37   1:33:59
37.03   1:34:03
24.02   7:39:58
28.02   7:40:01
24.04   7:40:04
24.02   7:40:07
25.35   7:40:10
26.69   7:40:13
32.04   7:40:16
28.02   11:05:43
30.71   11:05:46
29.36   11:05:49
18.68   11:05:52
54.72   11:05:55
34.69   10:31:34
25.03   10:31:38
56.04   10:31:40
44.03   10:31:43

I want to calculate the average of speeds per bins of 30 minutes. For example, the average speed during the 4th bin (1:31 - 2:00) is (54.72 + 49.37 + 37.03)/3. I have thought of converting hours, minutes and seconds to seconds from 00:00 and then have bins of 1800 seconds. I have tried to do use binned_statistic from scipy.stats but my main issue is that I cannot find a way to separate bins based on date and get the average of speeds.

Any ideas?

Answer 1

Converting to datetime and using pandas.Grouper + Offset Aliases :

df['date'] = pd.to_datetime(df.date)
df.groupby(pd.Grouper(key='date', freq='30min')).mean().dropna()

    speed
date    
2018-09-20 01:30:00     47.040000
2018-09-20 07:30:00     26.311429
2018-09-20 10:30:00     39.947500
2018-09-20 11:00:00     32.298000

Answer 2

Since your date column isn't really a date, it's probably more sensible to convert it to a timedelta that way you don't have a date attached to it.

Then, you can use dt.floor to group into 30 minute bins.

import pandas as pd

df['date'] = pd.to_timedelta(df.date)
df.groupby(df.date.dt.floor('30min')).mean()

Output:

              speed
date               
01:30:00  47.040000
07:30:00  26.311429
10:30:00  39.947500
11:00:00  32.298000