请求ajax不适用于php验证

Question

I want to use ajax in order to fadeIn a loader during PHP validation and returning the values from it to show visual effect messages, then fadeOut the loader when it finishes. But I did not managed to get a simple return from PHP validation in the .done function .

Can anyone help me please?

Index

<form action="php/valid.php" method="post" id="contact-form">
    <input id="name-contact" class="uk-input uk-width-1-1 uk-margin-small" type="text" name="name" placeholder="Name"><br>
    <input id="email-contact" class="uk-input uk-width-1-1 uk-margin-small" type="text" name="email" placeholder="Email"><br>
    <textarea id="message-contact" class="uk-input uk-textarea uk-width-1-1 uk-margin-small" name="message" placeholder="Message" style="height:200px"></textarea>
    <button id="contact-btn" class="uk-margin-small uk-button uk-button-secondary uk-width-1-1" type="submit" name="contact-form">Send</button>
</form>

JS

$(function() {
    var     data = {
        name: $('#name-contact').val(),
        email: $('#email-contact').val(),
        message: $('#message-contact').val()
    };
    $('#contact-form').on('submit', function(event) {
        $.ajax({
            url: 'php/valid.php',
            type: 'POST',
            dataType: 'json',
            data: data
        })
        .done(function(data) {
            if (data.status == 'success') {
                    console.log('Success !');
            } else if (data.status == 'error') {
                    console.log('Error !');
            }
        })
        .fail(function(error) {
            console.log(error);
        });
    });
});

PHP file

<?
    header('Content-Type: application/json');
    $error = false;
    $regex_name = '#^[\w\s\p{L}-]{2,30}$#iu';
    $regex_message = '#^[\s\S]{3,800}$#i';
    if (isset($_POST['contact-form'])) {
        $name = $_POST['name'];
        $from = $_POST['email'];
        $message = nl2br($_POST['message']);
        if (!empty($name) && !empty($from) && !empty($message)) {
               if (preg_match($regex_name, $name) && filter_var($from, FILTER_VALIDATE_EMAIL) && preg_match($regex_message, $message)) {
                    $error = array('type' => 'success');
               } else {
                    $error = array('type' => 'error', 'value' => 'There are some errors, please check your informations.');
               }
        } else {
            $error = array('type' => 'error', 'value' => 'Some fields are empty, please check your informations.');
        }
    }
    if (isset($error['type']) && $error['type'] == 'success') {
        $return_status['status'] = 'success';
        echo json_encode($return_status);
    }
    else {
        if (isset($error['type']) && $error['type'] == 'error') {
            $return_status['status'] = 'error';
            echo json_encode($return_status);
        }
     }
?>

Thank you.

Answer 1

First, you need to call event.preventDefault() to prevent the form from being submitted normally.

Second, you need to get the values of the inputs in the event handler. Your code is setting data when the page is loaded, before the user has filled in the form.

Third, your PHP script checks for the contact-form parameter. This is sent when you submit the form normally, but your AJAX request isn't setting it. You need to add it to data , or remove if (isset($_POST['contact-form'])) from the PHP (if valid.php is never used for anything else, this check is probably not necessary).

 $(function() { $('#contact-form').on('submit', function(event) { event.preventDefault(); var data = { name: $('#name-contact').val(), email: $('#email-contact').val(), message: $('#message-contact').val(), "contact-form": true }; $.ajax({ url: 'php/valid.php', type: 'POST', dataType: 'json', data: data }) .done(function(data) { if (data.status == 'success') { console.log('Success !'); } else if (data.status == 'error') { console.log('Error !'); } }) .fail(function(error) { console.log(error); }); }); }); 

Answer 2

Change button type to button:

<button id="contact-btn" class="" type="button" name="contact-form">Send</button>

Change your js code like below :

$(document).ready(function () {
    $('#contact-btn').click(function(event) {
        var data = {
            name: $('#name-contact').val(),
            email: $('#email-contact').val(),
            message: $('#message-contact').val()
        };
        $.ajax({
            url: 'php/valid.php',
            type: 'POST',
            dataType: 'json',
            data: data,
            success: function(response) {
                if (response.status == 'success') {
                        console.log('Success !');
                } else if (response.status == 'error') {
                        console.log('Error !');
                } else
                    console.log("Somthing went wrong....")
            },
            error:function(){
                console.log("error");
              }
        });
    });
});