[英]Python Flask failing on api.route('/')
Why does this simple code fail?为什么这个简单的代码会失败? I don't get it:
我不明白:
import sys
import pprint
import socket
from flask import Flask, request
from flask_restplus import Resource, Api
app = Flask(__name__)
api = Api(app)
@api.route('/')
class Root():
def get(self):
return { 'I am get.' }
def post(self):
return { 'I am post.' }
I've seen ...route('/') used in examples, like http://blog.luisrei.com/articles/flaskrest.html , but this is what I get:我已经看到 ...route('/') 在示例中使用,例如http://blog.luisrei.com/articles/flaskrest.html ,但这就是我得到的:
Python 3.6.6 |Anaconda, Inc.| (default, Jun 28 2018, 17:14:51)
[GCC 7.2.0] on linux
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "/project/libdev_py/libmems_conda/envs/py36/lib/python3.6/site-packages/flask_restplus/namespace.py", line 92, in wrapper
self.add_resource(cls, *urls, **kwargs)
File "/project/libdev_py/libmems_conda/envs/py36/lib/python3.6/site-packages/flask_restplus/namespace.py", line 82, in add_resource
api.register_resource(self, resource, *ns_urls, **kwargs)
File "/project/libdev_py/libmems_conda/envs/py36/lib/python3.6/site-packages/flask_restplus/api.py", line 261, in register_resource
self._register_view(self.app, resource, *urls, **kwargs)
File "/project/libdev_py/libmems_conda/envs/py36/lib/python3.6/site-packages/flask_restplus/api.py", line 273, in _register_view
previous_view_class = app.view_functions[endpoint].__dict__['view_class']
KeyError: 'view_class'
>>>
基于https://flask-restplus.readthedocs.io/en/stable/quickstart.html ,尝试class Root(Resource):
,而不仅仅是class Root():
。
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