打印字符串模式的Java程序

Question

if the input string is "ADMINISTRATIONS" the pattern should be like this A DM INI STRA TIONS

The last row should be completely filled

if the input string is "COMPUTER" the pattern should be like this C OM PUT ER**

the incomplete last row should be filled with *

i have got the pattern but couldnt print the stars.

    int k=0;
    String str = "computer";
    String[] s=str.split("\\B");
    for(int i=0; i<s.length;i++){
        for(int j=0; j<i;j++){
            if(k<s.length){
        System.out.println(s[k]);
        k++;
            }
    }
        System.out.println();

Help me to solve this.

Answer 1

Written when no code was provided - earlier it was tagged under C .

It is simple recursive to print string in the way described in the problem statement. Here is a C equivalent code to do this (as this question has been tagged in Java as well):

  #include<stdio.h>

  int i=1;

  void fun(char c[])
  {
      int j=0;

      while((j<i)&&(c[j]))
      {
          printf("%c",c[j++]);
      }
      while((c[j]=='\0')&&(j<i))
      {
          printf("*");
          ++j;
      }

      ++i;
      if(c[j])
      {
          printf(" ");
          fun(c+j);
      }
  }

  int main(void)
  {
      char c[]="computer";
      fun(c);
      return 0;
  }

OUTPUT:

 c om put er**

If you want to replace the \\0 check then you can use the length of string as a check as I am not aware if null termination is there in Java.

Answer 2

Java version, since comments are not appropriate for code:

String str = "computer";
int k = 0;
for (int i=0; k<str.length(); i++) {  // note: condition using k
    for (int j=0; j<i; j++) {
        if (k < str.length()) {
            System.out.print(str.charAt(k++));
        } else {
            System.out.print("*");  // after the end of the array
        }
    }
    System.out.println();
}

^{not tested, just an idea}

Notes: there is no need to use split since we want each character of the string - we can use charAt (or toCharArray ). Using print instead of println to not change lines.