如何打印一个列表中另一个列表中的元素？

Question

I have 2 lists that have a few similar value, what I want is to print out the values that are only in both lists. I tried a list comprehension but it gives me a boolean list:

a=[2,3,1,5,7]
b=[2,5,9,3,5,10]
c=[d in a for d in b]
print (c)

from this I get the results below:

[True, True, False, True, True, False]

but I wanted the numbers familiar in both lists.

Answer 1

You can conditionally take only the d that are in a from b :

c = [d for d in b if d in a]
# Here -----------^

Answer 2

let us see this code : [d in a for d in b] , d in a will return True or False because it equal to

if d in a:
    return True 
else:
    return False

So the result of [d in a for d in b] is [True, True, False, True, True, False]

The best way to wanted the numbers familiar in both lists is:

a=[2,3,1,5,7]
b=[2,5,9,3,5,10]
print(list(set(a) & set(b))) # [2, 3, 5]

Answer 3

You could use a set to compare the values, however I don't believe this preserves order:

c = set(a) & set(b)
print('\n'.join(str(i) for i in c))