如何处理警告：未经检查调用 'ObservableField(T)' 作为原始类型 'android.databinding.ObservableField' 的成员

Question

The following code:

public ObservableField ofFoo = new ObservableField("");

Generates the following warning:

Unchecked call to 'ObservableField(T)' as a member of raw type 'android.databinding.ObservableField'

What is the right way to avoid this warning?

Answer 1

ObservableField<String> ofFoo = new ObservableField<>("");

虽然我不明白你为什么要把一个空字符串包装成一个可观察的对象。

Answer 2

See Android Document

ObservableField is an object wrapper to make it observable.

If you want make an object observable then you wrap it with ObservableField .

If you want a String observable object then

ObservableField<String> ob = new ObservableField();

If you need an integer

ObservableField<Integer> ob = new ObservableField();

So you will get a warning when you initialise this android.databinding.ObservableField<T> generic class without an type.

There are other predefined classes too.

ObservableArrayList list;
ObservableBoolean aBoolean;
ObservableInt anInt;
ObservableMap map;