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使用[XmlAttribute]对xml反序列化的空值

[英]Null value on xml deserialization using [XmlAttribute]

I have the following XML; 我有以下XML;

<?xml version="1.0" encoding="UTF-8" ?>
<feedback>
  <report_metadata>
    <org_name>example.com</org_name>
  </report_metadata>
</feedback>

and the following Feedback.cs class; 和以下的Feedback.cs类;

   [XmlRoot("feedback", Namespace = "", IsNullable = false)]
    public class Feedback
    {
        [XmlElement("report_metadata")]
        public MetaData MetaData { get; set; }
    }


    [XmlType("report_metadata")]
    public class MetaData
    {
        [XmlAttribute("org_name")]
        public string Organisation { get; set; }
    }

When I attempt to deserialize, the value for Organisation is null. 当我尝试反序列化时,Organization的值为null。

var xml = System.IO.File.ReadAllText("example.xml");
var serializer = new XmlSerializer(typeof(Feedback));
using (var reader = new StringReader(input))
{
    var feedback = (Feedback)serializer.Deserialize(reader);

}

Yet, when I change Feedback.cs to the following, it works (obviously the property name has changed). 然而,当我将Feedback.cs更改为以下内容时,它可以工作(显然属性名称已更改)。

[XmlType("report_metadata")]
public class MetaData
{
    //[XmlAttribute("org_name")]
    public string org_name { get; set; }
}

I want the property to be Organisation, not org_name. 我希望该属性是组织,而不是org_name。

In the example XML file org_name is an XML element, not an XML attribute. 在示例XML文件中, org_name是XML元素,而不是XML属性。 Changing [XmlAttribute("org_name")] to [XmlElement("org_name")] at the Organisation property will deserialize it as an element: Organisation属性中将[XmlAttribute("org_name")]更改为[XmlElement("org_name")]会将其反序列化为元素:

[XmlElement("org_name")]
public string Organisation { get; set; }

probably just typo 可能只是错字

[XmlAttribute("org_name")]
public string Organisation { get; set; }

was supposed to be 应该是

[XmlElement("org_name")]
public string Organisation { get; set; }

Try to modify your Xml classes like 尝试修改你的Xml类

[XmlRoot(ElementName = "report_metadata")]
public class MetaData
{
    [XmlElement(ElementName = "org_name")]
    public string Organisation { get; set; }
}

[XmlRoot(ElementName = "feedback")]
public class Feedback
{
    [XmlElement(ElementName = "report_metadata")]
    public MetaData MetaData { get; set; }
}

Then you will get your desired output like 然后你会得到你想要的输出

class Program
{
    static void Main(string[] args)
    {
        Feedback feedback = new Feedback();
        var xml = System.IO.File.ReadAllText(@"C:\Users\Nullplex6\source\repos\ConsoleApp4\ConsoleApp4\Files\XMLFile1.xml");
        var serializer = new XmlSerializer(typeof(Feedback));
        using (var reader = new StringReader(xml))
        {
            feedback = (Feedback)serializer.Deserialize(reader);
        }

        Console.WriteLine($"Organization: {feedback.MetaData.Organisation}");
        Console.ReadLine();
    }
}

Output: 输出:

在此输入图像描述

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