如何在Pandas DataFrame行上打印列名？

Question

I have this DataFrame:

 df = pd.DataFrame({'day':['1/1/2017','1/2/2017','1/3/2017','1/4/2017','1/5/2017','1/6/2017','1/7/2017'],
                     'event':['Rain','Sunny','Snow','Snow','Rain','Sunny','Sunny'],
                   'temperature': [32, 35, 28,24,32,31,''],'windspeed':[6,7,2,7,4,2,'']})
 df

I am trying to find the headers for the missing values on index 6:

for x in df.loc[6]:
if x == '':
    print(df.columns.values)
else: print(x)

I have tried searching and the closest I could get was what I have now. Ultimately I'm trying insert these values into the dataframe: temperature = 34, windspeed = 8.

But my first step was simply trying to build the loop/if statement that says if x=='' & [COLUMN_NAME] == 'temperature'... and that is where I got stuck. I'm new to python, just trying to learn Pandas. I need to only return the column I'm on, and not a list of all the columns.

Answer 1

There are better ways to do this, but this works.

for col, val in df.loc[6].iteritems():
    if not val: # this is the same as saying "if val == '':"
        print(col)
    else:
        print(val)

Answer 2

Modified from your code:

for i,x in enumerate(df.loc[6]):
    if x == '':
        print(df.columns[i])
    else: print(x)

Answer 3

I would use list comprehension as follows:

listOfNulls = [ind  for ind in df.loc[6].index if df.loc[6][ind] == '']

and when I print the listOfNulls , I get:

>>>> print(listOfNulls)
Out: ['temperature', 'windspeed']

The key here is it understand that df.loc[6] is a pandas Series which has indices. We are using the values of the Series to get the indices.