SQL：多对多关系和'ALL'子句

Question

I have a table products and a table locations which are linked together in a many-to-many relationship with a table products_locations . Now a client can select a set of products, and I want to run a query that selects only the locations, where ALL of the selected products are available.

This seemed pretty straight forward at first, but I see myself being quite baffled by how to achieve this. I initially thought I could get all the correct location-ids with something like

SELECT location_id
FROM products_locations
WHERE product_id = ALL [the user selected product ids]

But on second thought that does not appear to make sense either (the structure of products_locations is quite simply [product_id, location_id] .

Any suggestion on how to structure such a query would be appreciated. I feel like I am overlooking something basic..

EDIT: I am using mysql syntax/dialect

Quick sample: Given the following tables

| products   | | locations | | products_locations       |
| id | name  | | id | name | | product_id | location_id |
|------------| |-----------| |--------------------------|
| 1  | prod1 | | 1  | locA | | 1          | 2           |
| 2  | prod2 | | 2  | locB | | 2          | 1           |
| 3  | prod3 | |-----------| | 2          | 2           |
|------------|               | 3          | 1           |
                             |--------------------------|

If a user selects products 1 and 2, the query should return only location 2. If the user selects products 2 and 3, the query should return location 1. For 1, 2, and 3, no location would be valid, and for product 2, both locations would be valid.

Answer 1

I figured out a query that achieves what I need. Though it is not as clean as I had hoped, it seems to be a robust approach to what I'm trying to query:

SELECT t.location_id
FROM (SELECT location_id, COUNT(*) as n_hits
      FROM products_locations
      WHERE product_id IN [the user selected products]
      GROUP BY location_id) t
WHERE n_hits = [the number of user selected products];

---

Explanation:

1. I create a temporary table t which contains every location_id that has at least one matching product in the user's selection, together with the number of times that location matches a product in the user's selection. This is achieved by grouping the query by location_id .
2. I select the location_id (s) from that temporary table t , where the number of hits is equal to the number of products the user had selected. If that number is lower, I know that at least one product did not match that location.