[英]Deepstream 1 - n relation
I'm trying to build a user notification
using Deepstream.io
. 我正在尝试使用
Deepstream.io
构建user notification
。 I'm using deepstream.io-storage-mongodb
for storage. 我正在使用
deepstream.io-storage-mongodb
进行存储。 My data structure: 我的数据结构:
User
=================
id - email - others
Notication
=================
userId - notification
I'm try to implement 1-n modelling deepsteam tutorial . 我正在尝试实现1-n建模deepsteam教程 。 But I can't understand how can I do this.
但是我不明白该怎么办。 How can I store pointer or how can I point towards a
List
? 如何存储指针或如何指向
List
? Or how can I implement notification using deepstream
? 或者如何使用
deepstream
实施通知?
Thanks in Advance. 提前致谢。
you can try as like as given below (I'm using JS
): 您可以尝试如下所示(我使用
JS
):
Receive Notication 收到通知
var client = deepstream( 'localhost:6020' );
client.login();
// Unique Identification for user
let uniqueId = `userId:${userId}`;
// Mongodb collection : Notification
statusRecord = client.record.getList("Notification/" + uniqueId);
statusRecord.subscribe(function(data) {
data.forEach(function(name) {
var record = client.record.getRecord(name);
record.whenReady(function(r) {
// all notification
console.log( "r ==> ", r.get() );
});
});
});
Send Notification 发送通知
const ds = deepstream( 'localhost:6020' );
ds.login();
// userId
const list = this.ds.record.getList( `Notification/${userId}` );
// id for notification
let id = `Notification/${this.ds.getUid()}`;
let record = this.ds.record.getRecord(id);
record.set( {
message: 'information'// save notification data
});
list.addEntry(id);
Hope it will solve your problem. 希望它能解决您的问题。
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.