如何验证IP地址以确保用户在四个部分中输入3位数字？

Question

I was able to create a script to validate IP address correctly like this,

var ipformat = /^(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)$/;

if(g_form.getValue('src_nw_ip_hdcc').match(ipformat)){
    return true;
}else{
    alert("You have entered an invalid Network IP Address!");
    return false;
}

The results was great but until then they made a unusual request that they require me to validate user enter 3 digits and not allow enter 1 or 2 digits like for example, user can't enter 115.42.150.37, instead must enter 115.042.150.037. How can I add verify to ensure they enter 3 digits?

Answer 1

In your code it has [01]?[0-9][0-9] . It says it can have a leading 0 or 1 or not followed by two numbers. Simple fix is to remove the ? where it makes the 0 and 1 optional

/^(25[0-5]|2[0-4][0-9]|[01][0-9][0-9])\.(25[0-5]|2[0-4][0-9]|[01][0-9][0-9])\.(25[0-5]|2[0-4][0-9]|[01][0-9][0-9])\.(25[0-5]|2[0-4][0-9]|[01][0-9][0-9])$/

Answer 2

You can do it by removing alls "?" in the regex. This way your regex requires 3 digits every time and accepts things like 192.168.001.001

^(25[0-5]|2[0-4][0-9]|[01][0-9][0-9])\.(25[0-5]|2[0-4][0-9]|[01][0-9][0-9])\.(25[0-5]|2[0-4][0-9]|[01][0-9][0-9])\.(25[0-5]|2[0-4][0-9]|[01][0-9][0-9])$

Answer 3

I think this regex will do the job. Hope this helps.

 const regex = /^(((25[0-5])|(2[0-4][0-9])|([01][0-9]{2}))\\.){3}((25[0-5])|(2[0-4][0-9])|([01][0-9]{2}))$/g; console.log('Should match'); console.log('255.255.255.255'.match(regex)); console.log('012.000.255.001'.match(regex)); console.log('000.000.000.000'.match(regex)); console.log('Should not match'); console.log('255.255.255.'.match(regex)); console.log('255.255.255.-1'.match(regex)); console.log('.255.255.'.match(regex)); console.log('255.275.255.'.match(regex)); console.log('255.275.255.1'.match(regex)); console.log('25.5.55.1'.match(regex)); 

Answer 4

You can use split() and every() in conjunction to get that validation work:

 function checkIp(ip) { var isCorrect = ip.split('.').every(addr => addr.length === 3); if (isCorrect) { return 'Ip address is correct'; } return 'Ip address is incorrect'; } var ip = '115.042.150.037'; console.log(checkIp(ip)); ip = '11.042.150.037'; console.log(checkIp(ip));