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Python3列出与特定文件夹名称相同级别的所有文件/目录

[英]Python3 listing all files/directories on same level as certain folder name

I have a path like this: 我有这样一条路:

/my/path/to/important_folder

on the same level, I have other files and folders that I want to list when I reach the same level as important_folder . 在同一水平上,我还有其他的文件和文件夹,我想,当我达到同一水平列出important_folder

My folder could be deeper, so I need to traverse through the folders until I reach important_folder keep searching. 我的文件夹可能更深,因此我需要遍历这些文件夹,直到到达important_folder继续搜索。 Once found, list all files/folders in that same level. 找到后,列出同一级别的所有文件/文件夹。

How can I achieve this? 我该如何实现?

With os.walk , you can do this: 使用os.walk ,您可以执行以下操作:

import os
for path, dirs, files in os.walk('/my/path'):
    if path == 'important_folder':
        for name in dirs + files:
            print(os.path.join(path, name))

Or you can use glob.iglob with recursive=True : 或者,您可以将glob.iglobrecursive=True

import glob
for name in glob.iglob('/my/path/**/important_folder/*', recursive=True):
    print(name)

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