为了避免使用python regex引号内的模式

Question

I am trying to match a multi line string str as follows,

call fun (TP$NULL, 
    ERROR_CODE,
    PROG_ID || 'Password Incorrect, Please try again') /*END*/

I want to process this string with out missing anythings (ie, spaces, tab & newline)

I tried get it by using comma which separate three arguments

re.search (r'(\s*call\s+fun\s*\()(.+),(.+),(.+)(\).*)', str, re.DOTALL).groups

('call fun (', 'TP$NULL, ERROR_CODE', " PROG_ID || 'Password Incorrect", " Please try again'", ') /*END*/')

see the comma inside quotes in the third argument creates problem.

When I am trying the regex below,

re.search (r'call fun \((.+),(.+), (.*\'.*,.*\'.*)\)' , str, re.DOTALL).groups()

above case is working but below string str2 is not working.

call fun (TP$NULL, err, PROG_D) 

I tried negative look ahead as follows, but no luck,

re.search (r'call fun \((.+),(.+),(?!\'.+\')(.+)\)' , str, re.DOTALL).groups()

Answer 1

you likely just want the first 2 groups to not be greedy, eg using your previous to last version:

>>> for g in re.search (r'call fun \((.+?),(.+?),(.*)\)', str2, re.DOTALL).groups():
...     print(g)
...
TP$NULL
err
PROG_D


>>> re.search (r'call fun \((.+?),(.+?),(.*)\)', str1, re.DOTALL).groups()
('TP$NULL', ' \n    ERROR_CODE', "\n    PROG_ID || 'Password Incorrect, Please try again'")

should cover both presented cases to an acceptable state