简体   繁体   English

JavaScript:将具有父键的对象数组转换为父/子树(包括没有父对象的对象)

[英]JavaScript: Convert array of objects with parent keys to parent / child tree (including objects with no parent)

I have a list of objects with parent keys that describes several levels of nested parent / child relationships.我有一个带有父键的对象列表,它描述了嵌套父/子关系的几个级别。

const table =[
    {
        "id": 791,
        "sortOrder": 0,
        "parentCategoryId": 833
    },
    {
        "id": 790,
        "sortOrder": 0,
        "parentCategoryId": 833
    },
    {
        "id": 845,
        "sortOrder": 0,
        "parentCategoryId": 847
    },
    {   
        "id": 844,
        "sortOrder": 0,
        "parentCategoryId": 842
    },
    {   
        "id": 802,
        "sortOrder": 0,
        "parentCategoryId": 847
    },
    {   
        "id": 788,
        "sortOrder": 0,
        "parentCategoryId": 833
    },
    {    
        "id": 863,
        "sortOrder": 0,
        "parentCategoryId": 863
    },
    {    
        "id": 858,
        "sortOrder": 0,
        "parentCategoryId": 858
    },
    {    
        "id": 867,
        "sortOrder": 0,
        "parentCategoryId": 867
    },
    {    
        "id": 871,
        "sortOrder": 0,
        "parentCategoryId": 867
    },
    {    
        "id": 801,
        "name": "Tickets",
        "sortOrder": 0,
        "parentCategoryId": 847
    },
    {    
        "id": 792,
        "sortOrder": 0,
        "parentCategoryId": 833
    },
    {    
        "id": 797,
        "sortOrder": 0,
        "parentCategoryId": 847
    },
    {    
        "id": 789,
        "name": "Hot food",
        "sortOrder": 0,
        "parentCategoryId": 833
    },
    {    
        "id": 798,
        "sortOrder": 0,
        "parentCategoryId": 847
    },
    {    
        "id": 671,
        "sortOrder": 0,
        "parentCategoryId": 847
    },
    {    
        "id": 833,
        "sortOrder": 0,
        "parentCategoryId": 833
    },
    {    
        "id": 796,
        "sortOrder": 0,
        "parentCategoryId": 847
    },
    {    
        "id": 843,
        "sortOrder": 0,
        "parentCategoryId": 842
    },
    {    
        "id": 840,
        "sortOrder": 0,
        "parentCategoryId": 793
    },
    {    
        "id": 868,
        "sortOrder": 0,
        "parentCategoryId": 868
    },
    {    
        "id": 851,
        "sortOrder": 0,
        "parentCategoryId": 851
    },
    {    
        "id": 839,
        "sortOrder": 0,
        "parentCategoryId": 847
    },
    {    
        "id": 793,
        "sortOrder": 0,
        "parentCategoryId": 839
    },
    {    
        "id": 859,
        "sortOrder": 0,
        "parentCategoryId": 859
    },
    {   
        "id": 805,
        "sortOrder": 0,
        "parentCategoryId": 859
    },
    {    
        "id": 856,
        "name": "DRINKS",
        "sortOrder": 0,
        "parentCategoryId": 805
    },
    {    
        "id": 870,
        "sortOrder": 0,
        "parentCategoryId": 856
    },
    {    
        "id": 787,
        "sortOrder": 0,
        "parentCategoryId": 833
    },
    {    
        "id": 786,
        "sortOrder": 0,
        "parentCategoryId": 833
    },
    {    
        "id": 799,
        "sortOrder": 0,
        "parentCategoryId": 847
    },
    {    
        "id": 852,
        "sortOrder": 0,
        "parentCategoryId": 852
    },
    {    
        "id": 795,
        "name": "Gents fragrance",
        "sortOrder": 0,
        "parentCategoryId": 847
    },
    {    
        "id": 864,
        "sortOrder": 0,
        "parentCategoryId": 864
    },
    {   
        "id": 854,
        "sortOrder": 0,
        "parentCategoryId": 854
    },
    {    
        "id": 865,
        "sortOrder": 0,
        "parentCategoryId": 865
    },
    {    
        "id": 869,
        "name": "GFI",
        "sortOrder": 0,
        "parentCategoryId": 869
    },
    {    
        "id": 785,
        "sortOrder": 0,
        "parentCategoryId": 833
    }
]

The issue is I don't have a root parent id with 0. I would like to order this in one array that shows in first level items where the id matches parentCategoryId , what means they are each a root and than each of them to have children within children.问题是我没有 0 的根父 ID。我想在一个数组中订购它,该数组显示在第一级项目中idparentCategoryId匹配,这意味着它们每个都是根,而不是每个都有孩子中的孩子。

Here is how far I got, but struggle to get this right:这是我走了多远,但很难做到这一点:

var root = { cid: 0, parent_id: null, children: []};
var node_list = { 0 : root};

     for (var i = 0; i < table.length; i++) {

       console.log('updated list', node_list)
       console.log('item in cat', table[i])

       // check if parent ID exsits in the list
       if (!node_list[table[i].parentCategoryId]) {

         console.log('not in the list');
         console.log('node_list[table[i].parentCategoryId]', table[i].parentCategoryId)
         if (table[i].parentCategoryId === table[i].cid) {
           console.log('it is the root');
           node_list[table[i].cid] = table[i];
         }    

       } else {

         const item = table[i];
         console.log('item is ', item)

         node_list[table[i].parentCategoryId].children = {
           ...node_list[table[i].parentCategoryId].children,
           ...item
         };
       }
     }

Expected result:预期结果:

const table =[
    {  
        "id": 791,
        "sortOrder": 0,
        "parentCategoryId": 833
    },
    {    
        "id": 790,
        "sortOrder": 0,
        "parentCategoryId": 833
    },
    {    
        "id": 845,
        "sortOrder": 0,
        "parentCategoryId": 847
    },
    {    
        "id": 844,
        "sortOrder": 0,
        "parentCategoryId": 842
    },
    {    
        "id": 802,
        "sortOrder": 0,
        "parentCategoryId": 847
    },
    {    
        "id": 788,
        "sortOrder": 0,
        "parentCategoryId": 833
    },
    {    
        "id": 863,
        "sortOrder": 0,
        "parentCategoryId": 863
    },
    {    
        "id": 858,
        "sortOrder": 0,
        "parentCategoryId": 858
    },
    {    
        "id": 867,
        "sortOrder": 0,
        "parentCategoryId": 867
    },
    {    
        "id": 871,
        "sortOrder": 0,
        "parentCategoryId": 867
    },
    {    
        "id": 801,
        "sortOrder": 0,
        "parentCategoryId": 847
    },    
    {    
        "id": 797,
        "sortOrder": 0,
        "parentCategoryId": 847,
        children:[
            {    
                "id": 792,
                "sortOrder": 0,
                "parentCategoryId": 797,
                children:[
                    {
                        "id": 671,
                        "sortOrder": 0,
                        "parentCategoryId": 792
                    },
                ]
            },
        ]
    },
    {    
        "id": 789,
        "name": "Hot food",
        "sortOrder": 0,
        "parentCategoryId": 833
    },
    {    
        "id": 798,
        "sortOrder": 0,
        "parentCategoryId": 847
    },
    {    
        "id": 833,
        "sortOrder": 0,
        "parentCategoryId": 833,
        children:[
            {    
                "id": 785,
                "sortOrder": 0,
                "parentCategoryId": 833
            },
            {
                "id": 786,
                "sortOrder": 0,
                "parentCategoryId": 833
            },
            {
                "id": 787,
                "sortOrder": 0,
                "parentCategoryId": 833
            },
        ]
    },
    {   
        "id": 796,
        "sortOrder": 0,
        "parentCategoryId": 847
    },
    {   
        "id": 843,
        "sortOrder": 0,
        "parentCategoryId": 842
    },
    {   
        "id": 840,
        "sortOrder": 0,
        "parentCategoryId": 793
    },
    {    
        "id": 868,
        "sortOrder": 0,
        "parentCategoryId": 868
    },
    {    
        "id": 851,
        "sortOrder": 0,
        "parentCategoryId": 851
    },
    {    
        "id": 839,
        "sortOrder": 0,
        "parentCategoryId": 847,
        children:[
            {
                "id": 793,
                "sortOrder": 0,
                "parentCategoryId": 839,
                children:[
                    {    
                        "id": 870,
                        "sortOrder": 0,
                        "parentCategoryId": 856
                    },
                ]
            },
        ]
    },
    {    
        "id": 805,
        "sortOrder": 0,
        "parentCategoryId": 859,
        children:[
            {
                "id": 856,
                "sortOrder": 0,
                "parentCategoryId": 805
            },
            {    
                "id": 859,
                "sortOrder": 0,
                "parentCategoryId": 805
            },
        ]
    },      
]

Looks like you want to add a children key with an array of values to the objects in your initial array where the id value corresponds to one or more parentCategoryId values from other objects in the array - and no object should be repeated as a parent or child in the array of nested objects.看起来您想向初始数组中的对象添加一个带有值数组的children键,其中id值对应于数组中其他对象的一个​​或多个parentCategoryId值 - 并且不应将任何对象作为父对象或子对象重复在嵌套对象数组中。

You could map the array to append children, and then filter to return just the root parents (and orphans).您可以map数组以追加子项,然后filter以仅返回根父项(和孤子)。 For example (working snippet below the example if you want to see the output):例如(如果您想查看输出,请在示例下方的工作片段):

const ids = table.map(x => x.id);

let result = table.map((parent) => {
  let children = table.filter((child) => {
    if (child.id !== child.parentCategoryId && child.parentCategoryId === parent.id) {
      return child;
    }
  });
  if (children.length) {
    parent.children = children;
  }
  return parent;
}).filter((obj) => {
  if (obj.id === obj.parentCategoryId || !ids.includes(obj.parentCategoryId)) {
    // include ultimate parents and orphans at root
    return obj;
  }
});

 const table = [{ "id": 791, "sortOrder": 0, "parentCategoryId": 833 }, { "id": 790, "sortOrder": 0, "parentCategoryId": 833 }, { "id": 845, "sortOrder": 0, "parentCategoryId": 847 }, { "id": 844, "sortOrder": 0, "parentCategoryId": 842 }, { "id": 802, "sortOrder": 0, "parentCategoryId": 847 }, { "id": 788, "sortOrder": 0, "parentCategoryId": 833 }, { "id": 863, "sortOrder": 0, "parentCategoryId": 863 }, { "id": 858, "sortOrder": 0, "parentCategoryId": 858 }, { "id": 867, "sortOrder": 0, "parentCategoryId": 867 }, { "id": 871, "sortOrder": 0, "parentCategoryId": 867 }, { "id": 801, "name": "Tickets", "sortOrder": 0, "parentCategoryId": 847 }, { "id": 792, "sortOrder": 0, "parentCategoryId": 833 }, { "id": 797, "sortOrder": 0, "parentCategoryId": 847 }, { "id": 789, "name": "Hot food", "sortOrder": 0, "parentCategoryId": 833 }, { "id": 798, "sortOrder": 0, "parentCategoryId": 847 }, { "id": 671, "sortOrder": 0, "parentCategoryId": 847 }, { "id": 833, "sortOrder": 0, "parentCategoryId": 833 }, { "id": 796, "sortOrder": 0, "parentCategoryId": 847 }, { "id": 843, "sortOrder": 0, "parentCategoryId": 842 }, { "id": 840, "sortOrder": 0, "parentCategoryId": 793 }, { "id": 868, "sortOrder": 0, "parentCategoryId": 868 }, { "id": 851, "sortOrder": 0, "parentCategoryId": 851 }, { "id": 839, "sortOrder": 0, "parentCategoryId": 847 }, { "id": 793, "sortOrder": 0, "parentCategoryId": 839 }, { "id": 859, "sortOrder": 0, "parentCategoryId": 859 }, { "id": 805, "sortOrder": 0, "parentCategoryId": 859 }, { "id": 856, "name": "DRINKS", "sortOrder": 0, "parentCategoryId": 805 }, { "id": 870, "sortOrder": 0, "parentCategoryId": 856 }, { "id": 787, "sortOrder": 0, "parentCategoryId": 833 }, { "id": 786, "sortOrder": 0, "parentCategoryId": 833 }, { "id": 799, "sortOrder": 0, "parentCategoryId": 847 }, { "id": 852, "sortOrder": 0, "parentCategoryId": 852 }, { "id": 795, "name": "Gents fragrance", "sortOrder": 0, "parentCategoryId": 847 }, { "id": 864, "sortOrder": 0, "parentCategoryId": 864 }, { "id": 854, "sortOrder": 0, "parentCategoryId": 854 }, { "id": 865, "sortOrder": 0, "parentCategoryId": 865 }, { "id": 869, "name": "GFI", "sortOrder": 0, "parentCategoryId": 869 }, { "id": 785, "sortOrder": 0, "parentCategoryId": 833 } ]; const ids = table.map(x => x.id); let result = table.map((parent) => { let children = table.filter((child) => { if (child.id !== child.parentCategoryId && child.parentCategoryId === parent.id) { return child; } }); if (children.length) { parent.children = children; } return parent; }).filter((obj) => { if (obj.id === obj.parentCategoryId || !ids.includes(obj.parentCategoryId)) { // include ultimate parents and orphans at root return obj; } }); // stringify just to flatten out SO console result for easier result scanning console.log(JSON.stringify(result));

We have a complex json file that we have to handle with JavaScript to make it hierarchical, in order to later build a tree.我们有一个复杂的 json 文件,我们必须用 JavaScript 处理它以使其具有层次结构,以便以后构建一棵树。 Every entry of the JSON array has − id − a unique id, parentId − the id of the parent node (which is 0 if the node is a root of the tree) level − the level of depth in the tree. JSON 数组的每个条目都有 - id - 唯一的 id, parentId - 父节点的 id(如果节点是树的根,则为 0) level - 树中的深度级别。

The JSON data is already "ordered", means that an entry will have above itself a parent node or brother node, and under itself a child node or a brother node. JSON 数据已经“有序”,这意味着条目将在其自身上方具有父节点或兄弟节点,在其自身下方具有子节点或兄弟节点。

 const arr = [   {      "id": "12",      "parentId": "0",      "text": "Man",      "level": "1",      "children": null   },   {      "id": "6",      "parentId": "12",      "text": "Boy",      "level": "2",      "children": null   },   {      "id": "7",      "parentId": "12",      "text": "Other",      "level": "2",      "children": null   },   {      "id": "9",      "parentId": "0",      "text": "Woman",      "level": "1",      "children": null   },   {      "id": "11",      "parentId": "9",      "text": "Girl",      "level": "2",      "children": null   } ]; const listToTree = (arr = []) => {   let map = {}, node, res = [], i;   for (i = 0; i < arr.length; i += 1) {      map[arr[i].id] = i;      arr[i].children = [];   };   for (i = 0; i < arr.length; i += 1) {      node = arr[i];      if (node.parentId !== "0") {         arr[map[node.parentId]].children.push(node);      }      else {         res.push(node);      };   };   return res; }; console.log(JSON.stringify(listToTree(arr), undefined, 4));

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM