如何将URL与python正则表达式匹配？

Question

我的问题是，我希望匹配HTML代码中的URL，如下所示： href='example.com'或使用" ，但我只想提取实际的URL。我尝试匹配它，然后使用数组魔术只获得数组，但由于正则表达式匹配是贪婪的 ，如果有超过1个有理匹配，则会有更多从一个'开始并以另一个URL结束' 。什么正则表达式适合我的需要？

Answer 1

I would recommend NOT using regex to parse HTML. Your life will be much easier if you use something like beautifulsoup !

It's as easy as this:

from BeautifulSoup import BeautifulSoup

HTML = """<a href="https://firstwebsite.com">firstone</a><a href="https://secondwebsite.com">Ihaveurls</a>"""

s = BeautifulSoup(HTML)

for href in s.find_all('a', href=True): print("My URL: ", href['href'])

Answer 2

In case if you want it to solve it using regular expression instead of using other libraries of python. Here is the solution.

import re
html = '<a href="https://www.abcde.com"></a>'
pattern = r'href=\"(.*)\"|href=\'(.*)\''
multiple_match_links = re.findall(pattern,html)
if(len(multiple_match_links) == 0):
     print("No Link Found")
else:
     print([x for x in list(multiple_match_links[0]) if len(x) > 0][0])