根据多个匹配键合并对象-Javascript

Question

I'm struggling with something that seems like it should be trivial. I have an array of objects:

const vehicles = [
{
    "sku": "1234",
    "year": "2004",
    "make": "Chevrolet",
    "model": "Avalanche",
},
{
    "sku": "1234",
    "year": "2006",
    "make": "Chevrolet",
    "model": "Avalanche",
},
{
    "sku": "1234",
    "year": "2009",
    "make": "Chevrolet",
    "model": "Silverado 1500",
},
{
    "sku": "1234",
    "year": "2006",
    "make": "Chevrolet",
    "model": "Silverado 1500",
}]

I would like to match on sku , make , and model and flatten the objects to have a final state of:

const mutatedVehicles = [
  {
    "sku": "1234",
    "years": ["2004", "2006"],
    "make": "Chevrolet",
    "model": "Avalanche",
  },
  {
    "sku": "1234",
    "years": ["2009", "2006"],
    "make": "Chevrolet",
    "model": "Silverado 1500"
  }]

I've actually worked with this in Python initially using dictionaries, but ultimately prefer some of the methods available in JS. I've tried using Array.forEach, Object.assign, and a few other methods and have come up short.

EDIT : I was asked to share some of the code I had tried - it's Python, not JS, as that's where I initially started.

def match_props(f, x):
    if f['sku'] == x['sku'] and f['year'] != x['year'] and f['make'] == x['make'] and f['model'] == x['model']:
        return True
    else:
        return False

fitments = [
    {
        "sku": "1234",
        "year": "2004",
        "make": "Chevrolet",
        "model": "Avalanche",
        "drive": "",
    },
    {
        "sku": "1234",
        "year": "2009",
        "make": "Chevrolet",
        "model": "Silverado 1500",
        "drive": "",
    },
    {
        "sku": "1234",
        "year": "2006",
        "make": "Chevrolet",
        "model": "Silverado 1500",
        "drive": "",
    },
]

merged = []

for f1 in fitments:
    pMerge = {}
    for f2 in fitments:
        if match_props(f1, f2):
            pMerge = {
                    "sku": f1['sku'],
                    "make": f1['make'],
                    "model": f1['model'],
                    "drive": f1['drive'],
                    "years": [y for y in [f1['year'], f2['year']]]
            }
        else:
            pMerge = f2
    if pMerge not in merged:
        merged.append(pMerge)


print(merged)

Answer 1

Use Array.reduce and Object.values

 const vehicles = [{"sku":"1234","year":"2004","make":"Chevrolet","model":"Avalanche"},{"sku":"1234","year":"2006","make":"Chevrolet","model":"Avalanche"},{"sku":"1234","year":"2009","make":"Chevrolet","model":"Silverado 1500"},{"sku":"1234","year":"2006","make":"Chevrolet","model":"Silverado 1500"}]; let result = Object.values(vehicles.reduce((a,{sku, year, make, model}) => { let id = sku + "_" + make + "_" + model; if(a[id]) a[id].years.push(year) else a[id] = {sku, make, model, years : [year]} return a; },{})); console.log(result); 

Answer 2

Although this answer overlaps with the one from Nikhil Aggarwal, it is enough different to show it. Instead of fixing the key fields, it focuses on the ones (here just year , but would be easy to extend to others) that have multiple values.

 const collect = (vehicles) => Object.values(vehicles.reduce((vs, v) => { const {year, ...veh} = v const key = JSON.stringify(veh); const vehicle = vs[key] || (vs[key] = {years: [], ...veh}) vehicle.years.push(year) return vs }, {})) const vehicles = [{"make": "Chevrolet", "model": "Avalanche", "sku": "1234", "year": "2004"}, {"make": "Chevrolet", "model": "Avalanche", "sku": "1234", "year": "2006"}, {"make": "Chevrolet", "model": "Silverado 1500", "sku": "1234", "year": "2009"}, {"make": "Chevrolet", "model": "Silverado 1500", "sku": "1234", "year": "2006"}] console.log(collect(vehicles))