通过JMeter正则表达式提取器从响应中提取ID

Question

I need to extract the session id and user id from the response through jmeter using regex.

Response:

\"SessionIdEncr\":\"TLGdqhQbxkEOziVJYXMD7Q==\",\"userIDEncr\":\"9xJbu+CGYN5RnnALeC8mKQ==\"

What is the regex for it?

Answer 1

Try using this pattern:

"SessionIdEncr":"([^"]+)","userIDEncr":"([^"]+)"

Not much to explain about the regex pattern, other than perhaps that ([^"]+) uses a trick to capture the values. It proceeds only so long as it doesn't capture another double quote, which would mean the closing quote for that key/value pair.

This would capture the base 64 encoded session ID and user ID, and would make them available in the extractor template as $1$ and $2$ .

Demo

Answer 2

1. Add Regular Expression Extractor as a child of the request which returns this text

2. Configure it like:

   • Name of created variable: anything meaningful, ie id

   • Regular Expression: \\\\"SessionIdEncr\\\\":\\\\"(.+?)",\\\\"userIDEncr\\\\":\\\\"(.+?)"

     Other fields can be left blank

     

3. You will be able to refer SessionID as ${id_g1} and UserId as ${id_g2} where required

   

References:

• JMeter: Regular Expressions
• Using Regular Expressions to Extract Tokens and Session IDs to Variables

Answer 3

In JMeter you can test/fix your regex using View Results Tree's Regexp Tester :

The Regexp Tester view only works for text responses. It shows the plain text in the upper panel. The "Test" button allows the user to apply the Regular Expression to the upper panel and the results will be displayed in the lower panel. The regular expression engine is the same as that used in the Regular Expression Extractor.

In your case create 2 Regular Expression Extractor s, for session ID use the following Regular Expression:

SessionIdEncr\\":\\"([^\\]+)

Get the User ID similarly.