在TypeScript中定义函数类型时返回函数“无法找到参数”

Question

I have trouble with defining a function type that returns another function in TypeScript.

This works:

type HandleDoc = (doc: any) => any
type SyncHookDoc = (updateStore, doc: any, store) => (void | HandleDoc)

But if I try in 1 line it does not work:

type SyncHookDoc = (updateStore, doc: any, store) => (void | (doc: any) => any)

Errors:

Cannot find name 'doc'.

'any' only refers to a type, but is being used as a value here.

Answer 1

您需要在函数签名周围附加一组() ：

type SyncHookDoc = (updateStore, doc: any, store) => (void | ((doc: any) => any))