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ngx-image-cropper 输出具有未定义名称的属性文件

[英]ngx-image-cropper Output property file having undefined name

I am using ngx-image-cropper to crop an image in my angular app.我正在使用ngx-image-cropper在我的 angular 应用程序中裁剪图像。 I use the Output property returning 'File' which is (imageCroppedFile) to be able to grab the cropped image.我使用输出属性返回“文件”,即 (imageCroppedFile) 能够抓取裁剪后的图像。 I need the cropped image to have a file name, so that I can iterate through the files on the back end using the name attribute, while it is by default undefined.我需要裁剪的图像有一个文件名,以便我可以使用 name 属性遍历后端的文件,而默认情况下它是未定义的。 How can I give it a name?我怎样才能给它起个名字? I tried the following: On the FormData,我尝试了以下操作:在 FormData 上,

var formData:any = new FormData();
console.log('The number of files is '+files.length);//Logs the number of files is 1

for(var i=0; i<files.length;i++) {
  formData.append("uploads[]", files[i].name, 'image'+i);
  console.log('File name '+ i + ' ' +files[i].name);//Logs File name 0 undefined
}

and on the method triggered by the cropping以及由裁剪触发的方法

imageCroppedFile(image: File) {
  this.filesToUpload = [];
  console.log('imageCroppedFile method '+image.name+ ' size is '+image.size);// Logs imageCroppedFile method undefined size is 380284
  this.filesToUpload[0]=image;
  console.log('The filesToUpload is '+this.filesToUpload[0].name);// Logs The filesToUpload is undefined
}

The uploader works without the cropper.上传器在没有裁剪器的情况下工作。

cast your file into blob, and you can name your blob by yourself将您的文件转换为 blob,您可以自己命名您的 blob

const blobImage = file as Blob;

Reference : https://github.com/Mawi137/ngx-image-cropper/issues/91#issuecomment-422252629参考: https : //github.com/Mawi137/ngx-image-cropper/issues/91#issuecomment-422252629

This works for me:这对我有用:

// grab the cropped area to file for upload
var b64File = this.dataURLtoFile(this.croppedImage, 'hello.jpg');  // you can name it anything.

dataURLtoFile(dataurl, filename): File {
        var arr = dataurl.split(','), mime = arr[0].match(/:(.*?);/)[1],
            bstr = atob(arr[1]), n = bstr.length, u8arr = new Uint8Array(n);
        while(n--){
            u8arr[n] = bstr.charCodeAt(n);
        }
        return new File([u8arr], filename, {type:mime});
    }

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