备份mysql数据库取特定表

Question

Hello This is the php code I use to Backup a mysql DATABASE, It takes all the DATABASE and all the tables, I want to take a particular table in the database instead of all tables. May someOne please tell me How to modify the php code PLEASE in order to take a single table instead of all tables? THis is the code:

<?php

/**
* Updated: Mohammad M. AlBanna
* Website: MBanna.info
*/


//MySQL server and database
$dbhost = 'localhost';
$dbuser = 'root';
$dbpass = '';
$dbname = 'novtech';
$tables = '*';

//Call the core function
backup_tables($dbhost, $dbuser, $dbpass, $dbname, $tables);

//Core function
function backup_tables($host, $user, $pass, $dbname, $tables = '*') {
    $link = mysqli_connect($host,$user,$pass, $dbname);

    // Check connection
    if (mysqli_connect_errno())
    {
        echo "Failed to connect to MySQL: " . mysqli_connect_error();
        exit;
    }

    mysqli_query($link, "SET NAMES 'utf8'");

    //get all of the tables
    if($tables == '*')
    {
        $tables = array();
        $result = mysqli_query($link, 'SHOW TABLES');
        while($row = mysqli_fetch_row($result))
        {
            $tables[] = $row[0];
        }
    }
    else
    {
        $tables = is_array($tables) ? $tables : explode(',',$tables);
    }

    $return = '';
    //cycle through
    foreach($tables as $table)
    {
        $result = mysqli_query($link, 'SELECT * FROM '.$table);
        $num_fields = mysqli_num_fields($result);
        $num_rows = mysqli_num_rows($result);

        $return.= 'DROP TABLE IF EXISTS '.$table.';';
        $row2 = mysqli_fetch_row(mysqli_query($link, 'SHOW CREATE TABLE '.$table));
        $return.= "\n\n".$row2[1].";\n\n";
        $counter = 1;

        //Over tables
        for ($i = 0; $i < $num_fields; $i++) 
        {   //Over rows
            while($row = mysqli_fetch_row($result))
            {   
                if($counter == 1){
                    $return.= 'INSERT INTO '.$table.' VALUES(';
                } else{
                    $return.= '(';
                }

                //Over fields
                for($j=0; $j<$num_fields; $j++) 
                {
                    $row[$j] = addslashes($row[$j]);
                    $row[$j] = str_replace("\n","\\n",$row[$j]);
                    if (isset($row[$j])) { $return.= '"'.$row[$j].'"' ; } else { $return.= '""'; }
                    if ($j<($num_fields-1)) { $return.= ','; }
                }

                if($num_rows == $counter){
                    $return.= ");\n";
                } else{
                    $return.= "),\n";
                }
                ++$counter;
            }
        }
        $return.="\n\n\n";
    }

    //save file , db-backup
    //$fileName = 'novtechDB-'.time().'-'.(md5(implode(',',$tables))).'.sql';
    $fileName = 'novtechDB'.'.sql';
    $handle = fopen($fileName,'w+');
    fwrite($handle,$return);

   if(fclose($handle)){
        echo "Done, the file name is: ".$fileName;
        exit; 
    }
}

I put $tables= array('myTable') Before the loop of the tables array[foreach($tables as $table)] , i'ts working now but it's giving me a error: Notice: Undefined variable: return. Please can SomeOne help me figure out what's wrong? How to fix it?

Answer 1

Before the loop of the tables array, set the array to the table you want to grab.

$tables = ['tale1','table2','table3'];
foreach($tables as $table)

Remove the code block that is commented //get all of the tables

Answer 2

Bravooooooooooooooo!!! I fixed it thank you #user3720435
Step 1: I Removed the code block that is commented //get all of the tables
Step 2:
I put $tables= array('myTable') Before the loop of the tables array[foreach($tables as $table)] , i'ts working now but it was giving me an error. Notice: Undefined variable: return.
Step 3: i fix it by putting return=null; before code block that is commented //Over tables