正则表达式：如何用空格/连字符（不包括数字）捕获单词？

Question

I have a dataset that looks like this:

Column1
-------
abcd - efghi 1234
aasdas - asdas 54321
asda-asd 2344
aasdas(asd) 5234

I want to be able to pull everything out that will exclude a number so it will look like this:

Column2
-------
abcd - efghi
aasdas - asdas
asda-asd
aasdas(asd)

This is my current regex:

df['Column2'] = df['Column1'].str.extract('([A-Z]\w{0,})', expand=True)

But it only extracts out the first word that excludes parenthesis and hyphens. Any help will be appreciated...thank you!

Answer 1

Like using replace

df.Column1.str.replace('\d+','')
Out[775]: 
0      abcd-efghi 
1    aasdas-asdas 
2        asda-asd 
3     aasdas(asd) 
Name: Column1, dtype: object
#df.Column1=df.Column1.str.replace('\d+','')

Answer 2

Just removing numbers will leave you with unwanted space characters.

This list comprehension removes all digits and keeps space characters, but removes them on the outside.

df['Column2'] = df['Column1'].apply(
                   lambda x: ''.join([i for i in x if not i.isdigit()]).strip())