从数组中查找所有可能的匹配字符串和子字符串

Question

I was trying to find a logic to select the matching string and matching substrings from an array. for ex:

I have a string "3-100" and an array of strings ["3", "3-1", "3-15", "3-",3-10", "3-100"].

when I loop over the array, and compare the strings, I should get true on 2 cases

"3" -> true,
"3-1" -> false,
"3-15" -> false,
"3-" -> false,
"3-10" -> false,
"3-100" -> true,

How can I achieve this. I tried .includes() which will return true for all cases except "3-15". Looking forward

Adjo

Answer 1

Using Regular expression

 var arr = ["3", "3-1", "3-15", "3-", "3-10", "3-100"]; var reg = /^3(-100)?$/; var result = arr.reduce((acc, val, ind) => { acc[ind] = reg.test(val); return acc; }, []); console.log(result); 

Answer 2

You could split the string and look for parts with Array#includes .

 var string = "3-100", parts = string.split('-').map((_, i, a) => a.slice(0, i + 1).join('-')), array = ["3", "3-1", "3-15", "3-", "3-10", "3-100"], result = array.map(s => parts.includes(s)); console.log(result); 

Answer 3

This should work and is backward compatible:

 var arr = ["3", "3-1", "3-15", "3-", "3-10", "3-100"]; var SearchA = "3"; var SearchB = "100"; for( var i=0; i< arr.length; i++) { console.log( arr[i] + " = " + ValidateValue(SearchA,SearchB,arr[i])) } function ValidateValue( A, B, value ){ var subarr = value.split("-"); if( subarr[0] != A ) return false; if( subarr.length == 1 ) return true; if( subarr[1] != B ) return false; return true; } 

You can also test it here: JS Bin