[英]output characters before and after a word then write to file
Im trying to get this code to find say 30 words before a specific word and 30 words after. 我正在尝试获取此代码以在特定单词之前找到30个单词,之后找到30个单词。 then i want it to writ'e my output to a new file. 然后我希望它将我的输出写入新文件。 i cant seem to figure out what i'm doing wrong as im pretty new to python. 我似乎无法弄清楚我在做什么错,因为我是python的新手。 any suggestions are more than welcome. 任何建议都值得欢迎。
def extract_text(file_name, to_find):
file_in = open('School.txt', 'r')
all_lines = file_in.readlines()
file_in.close()
new_text = all_text.replace ('\n', '|')
width = 30
to_find = 'boy'
new_text = all_text.replace ('\n', '|')
while new_text.find(to_find) != -1:
start = all_text.find(to_find)
begin = start - width
end = start + len(to_find) + width
print(new_text[begin:end])
out_put = new_text[begin:end]
f = open("School_boy.txt","w")
f.write(out_put)
f.close()
For text parsing, I would recommend using regex: 对于文本解析,我建议使用正则表达式:
import re
# Read the File
with open("file.txt", "r") as file:
text = file.read()
# replace newline with blank
text.replace('\n', '')
# parse the text
result = re.findall(r'(?P<before>\w+ ){30}target(P?<after>\w+ ){30}', text)
From there, all 30 words before are in a group called 'before' and all 30 words after are in a group called 'after' the target word -- in this example 'target'. 从那里开始,之前的所有30个单词都在称为“之前”的组中,而之后的所有30个单词都在称为目标单词的“之后”的组中。 RegEx can be really specific or really generic, depending on the pattern used. RegEx可以是特定的,也可以是通用的,具体取决于所使用的模式。 For example, the code above only allows for one space after a word and no punctuation. 例如,上面的代码只允许在单词后留一个空格,而不能使用标点符号。 For a guide on python regex: https://docs.python.org/3/howto/regex.html 有关python regex的指南: https : //docs.python.org/3/howto/regex.html
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