如何将PHP值传递给bash脚本？

Question

I am trying to get the php session_id with my bash script.

The echo $1 in my bash script works after running the bash script with exec in php. But the $1 in my same bash script {echo "delete $1";sleep1;}|telnet localhost 12345 is not getting the value.

.php code

$output = shell_exec('./test.sh '.escapeshellarg(session_id()));

.sh code

!/bin/sh
echo $1
{ echo "delete $1"; sleep 1; } | telnet localhost 12345

Result from $output

fa123a3b435c0534345f453554355dasds2a3dfsf7 NOT_FOUND

Answer 1

If you're trying to pass a command through telnet, you'll want to look at expect instead of sh , doing something like this:

#!/usr/bin/expect
set sid [lindex $argv 1]
spawn telnet localhost 12345
expect "#"
send "delete $sid"

Or just have PHP send the command.

$socket = socket_create(AF_INET, SOCK_STREAM, SOL_TCP);
$result = socket_connect($socket, "localhost", 12345);
$cmd = "delete " . session_id();
socket_write($socket, $cmd, strlen($cmd));
while ($out = socket_read($socket, 2048)) {
    echo $out;
}
socket_close($socket);