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在Ruby中使用&:语法调用自定义方法

[英]Calling custom method with &: syntax om Ruby

So basically I was looking at this simple example: 所以基本上我在看这个简单的例子:

%w[A B C].map(&:downcase)

And got interested in the &: syntax. 并对&:语法产生了兴趣。 After reading some articles I think I got the point (or at least I think so) so I've decided to implement something similar for Integer like this: 阅读一些文章后,我认为我明白了(或者至少是这样),所以我决定为Integer实施类似的操作:

class Integer
  def my_multiplier
    puts "66"
  end
end

And here I can get advantage of the &: syntax cause I am allowed to do so: 在这里,我可以利用&:语法,因为我可以这样做:

3.times(&:my_multiplier)

But of course the result is three times the number 66 . 但是结果当然是数字66三倍。

My questions is how to refactor my method so I can actually use the values from 3.times.. ? 我的问题是如何重构我的方法,以便实际上可以使用3.times..的值?

First of all, the syntax is &object , not &: . 首先,语法是&object ,不是&: &object calls .to_proc on the object. &object&object调用.to_proc

Now, assuming you'd like your multiplier to simply puts your integer multiplied by 66, you'd write it as: 现在,假设您希望乘数简单地将整数乘以66,则将其写为:

class Integer
  def my_multiplier
    puts 66 * self
  end
end

Which will result in 这将导致

2.5.1 :006 > 3.times(&:my_multiplier)
0
66
132

This is the equivalent of calling 这相当于调用

3.times { |i| i.my_multiplier }

You can also define your my_multiplier as a proc or a lambda, 您还可以将my_multiplier定义为proc或lambda,

2.5.1 :001 > p = ->(i) { puts i * 66 }
 => #<Proc:0x00005582b3ae5638@(irb):1 (lambda)> 
2.5.1 :002 > 3.times(&p)
0
66
132

It's unclear what you were shooting for with that method, but current integer will be available as self . 不清楚您使用该方法的目的是什么,但是当前整数将作为self So you can do something like this: 因此,您可以执行以下操作:

class Integer
  def double 
    self * 2
  end 

end

3.times.map(&:double) # => [0, 2, 4]

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