不安全的重定向到URL

Question

i'm create a class views on django, but get this error:

Unsafe redirect to URL with protocol 'products'

this is my code on the views:

class CreateProduct(CreateView):

    model = Product
    form_class = ProductForm
    template_name = "administrador/create_product.html"
    success_url = "products:admin_productos"

this is my urls:

url(r'^create_product$', CreateProduct.as_view(), name="create_product"),

i dont know why get this error..please some one idea..!!

thanks..!!

Answer 1

Success_url runs get_success_url method inside of CreateView and this method should return url via reverse lookup. This can be achieved by passing appropriate view to the reverse() .

success_url = reverse('products:admin_productos')

Answer 2

Your success URL is invalid - you need to pass an actual URL, not the name of one - ie, you need to reverse that name first. Change it to:

from django.urls import reverse_lazy

class CreateProduct(CreateView):

    success_url = reverse_lazy("products:admin_productos")

See the documentation for why reverse_lazy() is appropriate here instead of reverse() :

It is useful for when you need to use a URL reversal before your project's URLConf is loaded. Some common cases where this function is necessary are:

• providing a reversed URL as the url attribute of a generic class-based view.