如何计算字符串是否在列表的子字符串内？

Question

For example:

list_strings = 'dietcoke', 'dietpepsi', 'sprite' 

Here's what I did:

count = 0
list =
for ch in list_strings:

    if ch == sub:
        count += 1

print((list_strings, 'diet') == 2) is suppose to return True but it returns False .

Answer 1

I hope I understood you correctly.

Just use in to check if your substring is present in the mainstring.

list = ['dietcoke', 'dietpepsi', 'sprite']

Your function should look like this:

def myfuncname(list_strings, sub_string):
    count = 0
    for ch in list_strings:
        if sub_string in ch:
            count += 1
    return count

If we call count now, we get count == 2

>>> print(myfuncname(list_strings, 'diet') == 2) 
True

Hope that solved your problem.