[英]How can I call a function outside of the prototype in JavaScript?
How can I call the setTile
function outside of the scope of TopDownGame
? 我如何可以调用setTile
范围之外的功能TopDownGame
? I tried TopDownGame.Lesson31.setTile(x,y)
, but it doesn't work. 我尝试了TopDownGame.Lesson31.setTile(x,y)
,但是它不起作用。
var TopDownGame = TopDownGame || {};
TopDownGame.Lesson31 = function() {};
TopDownGame.Lesson31.prototype = {
setTile: function(x, y) {
console.log(tile);
}
};
If you have added to the prototype, then you must create an instance of the object to invoke a method: 如果已添加到原型,则必须创建对象的实例以调用方法:
var TopDownGame = TopDownGame || {};
TopDownGame.Lesson31 = function() {};
TopDownGame.Lesson31.prototype = {
setTile: function(x, y) {
console.log("setTile invoked");
},
};
var instance = new TopDownGame.Lesson31();
instance.setTile(3, 4);
You were trying to invoke it like it was a static method. 您试图像静态方法那样调用它。 If that's what you really want to do, define the method as a property of the function, not of the prototype. 如果那是您真正想要做的,则将方法定义为函数的属性,而不是原型的属性。
TopDownGame.Lesson31 = function() {};
TopDownGame.Lesson31.staticMethod = function() {
console.log('Static method invoked');
}
TopDownGame.Lesson31.staticMethod();
But if you really want to keep setTile
as a prototype method, but still invoke it, you can use the apply
method. 但是,如果您确实希望将setTile
保留为原型方法,但仍要调用它,则可以使用apply
方法。
var TopDownGame = TopDownGame || {};
TopDownGame.Lesson31 = function() {};
TopDownGame.Lesson31.prototype = {
setTile: function(x, y) {
console.log(`setTile invoked, this='${this}', x=${x}, y=${y}`);
},
};
new TopDownGame.Lesson31().setTile(3, 4);
TopDownGame.prototype.setTile.apply('actually a string', [5, 6]);
This will result in: 这将导致:
setTile invoked, this='[object Object]', x=3, y=4
setTile invoked, this='actually a string', x=5, y=7
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