[英]how to extract few before words after finding a keyword in text using python
I have a keyword "grand master" and I am searching for the keyword in the huge text. 我有一个关键字“ grand master”,并且正在大文本中搜索该关键字。 I need to extract 5 before words and 5 after words of the keyword (based on the position it might go to the next/before sentence also), and this keyword appears multiple times in huge text.
我需要提取该关键字的单词前5个单词和单词后5个单词(根据位置,它也可能转到下一个/句子之前的位置),并且此关键字在大文本中多次出现。
As a trail , first i tried to find the position of the keyword in the text, using text.find()
, and found the keywords at 4 different positions 首先,我尝试使用
text.find()
查找关键字在文本中的位置,并在4个不同的位置找到关键字
>>positions
>>[125, 567,34445, 98885445]
So tried to split the text based on spaces and taking first 5 words, 因此,我们尝试根据空格分割文本并采用前5个单词,
text[positions[i]:].split([len(keyword.split()):len(keyword.split())+5]
But how to extract the 5 words before that keyword? 但是,如何提取该关键字之前的5个单词?
你可以简单地使用
text[:position[i]].split()[-5:]
Use re module for this. 为此使用re模块。 For the first keyword match:
对于第一个关键字匹配:
pattern = "(.+) (.+) (.+) (.+) (.+) grand master (.+) (.+) (.+) (.+) (.+)"
match = re.search(pattern, text)
if match:
firstword_before = match.group(1) # first pair of parentheses
lastword_before = match.group(5)
firstword_after = match.group(6)
lastword_after = match.group(10)
Parentheses in the pattern indicates the group number. 模式中的括号表示组号。 First pair of parentheses corresponds to match.group(1), second pair of parentheses corresponds to match.group(2) and so on.
第一对括号对应于match.group(1),第二对括号对应于match.group(2),依此类推。 If you want all the groups you can use:
如果需要所有组,可以使用:
match.groups() # returns tuple of groups
or 要么
match.group(0) # returns string of groups
For all the keyword match in the text, use re.findall. 对于文本中所有匹配的关键字,请使用re.findall。 Read re for details.
阅读重新了解详情。
PS: There are better ways to write patterns. PS:有更好的方式来编写模式。 Thats just me being lazy.
那只是我偷懒。
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