如何使用减少，使用分解和递归来检查数组是否相等？

Question

How would you check two arrays for equality using the reduce helper, destructuring and recursion?

const isEqual = (arr1, arr2) => {
  // use reduce helper to check arrays for equality, use destructuring and recursion
}

So obviously isEqual([1,2,3], [1,2,3]) should return true for example and something like isEqual(["hello", "there"], ["good", "morning"]) should return false .

Answer 1

You can stringify the arrays by using JSON.stringify() before the comparison:

 const isEqual = (arr1, arr2) => { var flag = JSON.stringify(arr1)==JSON.stringify(arr2)? true : false; return flag; } console.log(isEqual([1,2,3], [1,2,3])); //true console.log(isEqual(["hello", "there"], ["good", "morning"])); //false console.log(isEqual([1, '2', 3], [1,2,3])); //false 

Answer 2

You could take a recursive approach with spread syntax ... and a check for the elements and by checking the length'.

 const isEqual = ([v, ...a], [w, ...b]) => { return v === w && a.length === b.length && (a.length === 0 || isEqual(a, b)); } console.log(isEqual([1, 2], [1, 2, 3])); console.log(isEqual([1, 2, 3], [1, 2, 3])); console.log(isEqual([1, 2, 3, 4], [1, 2, 3])); console.log(isEqual(["hello", "there"], ["good", "morning"]));